Heading upwards from -3, the four consecutive integers are -3, -1, 1, 3.
-3, -1, 1 and 3.
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Divide the sum of the three consecutive odd integers by 3: -3 /3 = -1. The smallest of these integers will be two less than -1 and the largest will be two more than -1, so the three consecutive odd integers will be -3, -1, and +1.
33/3 = 11 so the three are 9, 11 and 13
201
The first odd positive integers are "1" and "3" which the sum is 4.
After (3, 5, 7), you can't have any more such "triplets", since one of the three must needs be a multiple of 3.