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What is the largest prime number less than 1000?
997. To test that 997 is prime, we only need to test values up [997^.5], so up to 31. Using divisibility rules, we can immediately eliminate several possible divisors. Rule for 7: If you have a number, separate the last digit from the proceeding ones. Subtract twice the last digit from the number created from slicing off the last part. if that's divisible by seven, the whole number is. For example, take 343. 34-2(3) is 28, which is divisible by 7, so 343 is divisible by 7 Rule for 3: sum of digits is divisible by 3. Rule for 2: last digit is divisible by 2. Rule for 2^n: last n digits form a number that is divisible by 2^n Rule for 5: last digit is 5 or 0. Rule for 11: Difference of alternating sums of the digits, 432113 is divisible by 11 because (4+2+1)-(3+1+3) is divisible by eleven. Rule for 9: sum of digits is divisible by 9. Trying 13, 17, 19, 23, and 29, we see these all fail. So 997 is indeed prime.
Is twenty seven a prime number?
No, it is not a prime number because it can be divided by 9 to get 3. A prime number is only divisible by itself and one.
What seven-digit number can be rounded to 6300000?
6312345, to the nearest hundred thousand.
How do you write 0.770 In word form?
To write 0.770 in word form, you would say "zero point seven seven zero." This is because each digit after the decimal point is read individually. The first digit after the decimal point is read as "seven," the second digit as "seven" again, and the third digit as "zero."
Which is a prime number 4 6 7 9?
The prime number is seven, as it's only divisible by one and itself.Same goes for 11, 13, 17, and so on.
What a number even multiple of seven greater than 29 divisible by four and six digit add up to 12?
41
Liz thought of a seven-digit number. The number is divisible by 7. Five of the digits are 5s and the other two are 4 and 8. The first is 4 What is this number?
4,555,558
Can 117 be divided by 2?
58.5
What is the dvisibility rule for 7?
To find out if a number is divisible by seven, take the last digit, double it, and subtract it from the remaining digits of the number.If the result is divisible by 7 (including zero), then the original number is divisible by seven. If the new number is still too big, you can apply the rule again.Example: 406.First, double the last digit, 6. (6 times 2 equals 12.)Second, subtract that number from the remaining digits. (12 subtracted from 40 equals 28.)Third, if the result is divisible by seven, the whole number is. (7 divides equally into 28.)Thus, since the result is divisible by seven, we can conclude that 406 is divisible by seven.If the result is still to big, repeat this procedure.Example: 7,805.Double the last digit, (makes 10,) subtract it from remaining digits, (780 minus 10 equals 770.)770 is still to big a number to easily determine whether it is divisible by seven, so it is best to repeat the procedure, like so:Double the last digit, which is a little weird since the last digit is zero, but 0 plus 0 still equals zero. (0 times 2 equals zero.) Subtract from remaining digits, (77 minus 0 equals 77.)77 is divisible by 7, so we can conclude that 7,805 is divisible by seven.
What is 53627?
53627 is a whole number that falls between 53626 and 53628. It is a five-digit number that is not divisible by 2.
Is 87 divisible by 7?
No, 87 is not divisible by 7. To determine if a number is divisible by 7, you can use the rule that states a number is divisible by 7 if the difference between twice the digit in the ones place and the number formed by the other digits is either 0 or a multiple of 7. In this case, the number formed by the other digits is 8, and twice the digit in the ones place is 14. The difference between 14 and 8 is 6, which is not a multiple of 7, so 87 is not divisible by 7.
When do you say that a no is divisible by 7?
When a number is a multiple of seven it is also divisible by seven.
510 is NOT divisible by what number?
510 is not divisible by seven.
What is the trick in finding if something is divisible by 7?
To find out if a number is divisible by seven, take the last digit, double it, and subtract it from the rest of the number.Example: If you had 203, you would double the last digit to get six, and subtract that from 20 to get 14. If you get an answer divisible by 7 (including zero), then the original number is divisible by seven. If you don't know the new number's divisibility, you can apply the rule again. Source~http://mathforum.org/k12/mathtips/division.tips.html But with incrediby large numbers you're just better off just dividing to see.
What is the smallest number divisible by eight seven and five?
The smallest number divisible by eight seven and five is 280.
How many seven digit numbers contain the number seven at least once?
To find the total number of seven-digit numbers that contain the number seven at least once, we can use the principle of complementary counting. There are a total of 9,999,999 seven-digit numbers in total. To find the number of seven-digit numbers that do not contain the number seven, we can count the number of choices for each digit (excluding seven), which is 9 choices for each digit. Therefore, there are 9^7 seven-digit numbers that do not contain the number seven. Subtracting this from the total number of seven-digit numbers gives us the number of seven-digit numbers that contain the number seven at least once.
Why does divisibility rule for 7 work?
there is one for seven although its not very useful. take the last digit trunccate it and double it then subtract the rest. If the resulting number is divisible by seven, so was the origanil
