Sure. They obviously can't all be whole numbers, since the product of any list of
whole numbers is another whole number. Once we're relieved of that constraint,
we can start churning them out:
1 x 2 x 1.2
1 x 3 x 0.8
1 x 4 x 0.6
1 x 5 x 0.48
1 x 6 x 0.4
1 x 8 x 0.3
1 x 10 x 0.24
1 x 12 x 0.2
2 x 3 x 0.4
2 x 4 x 0.3
2 x 5 x 0.24
2 x 6 x 0.2
.
.
etc.
Three and Seven
10 and 28
To find the LCM, you multiply the numbers together and then divide by the HCF. In this case, we don't know the numbers, but we have the HCF (13) and we have the product of the numbers (1690). Thus all you do is divide 1690 by 13 to get: 1690/13 = 130 And thus the LCM of two numbers whose hcf is 13 and product is 1690 is 130.
11 and 13
13 and 5 13+5=18 13x5=65
24,25,26
Three and Seven
3 and 84.
15 and 18
"The sum of a number and three times another number is 18. find the numbers if their product is a maximum?"
1. find the product of the first two 2. multiply that product with the third number
root 2 * root 2 = 2
19
If three is subtracted from the product to get 17, the product must be 20. Then find what number can be multiplied by 5 to get 20. The answer is 4.
When you have this kind of question, try to break it down, maybe first by a 2 or 3 or 10. For your question, find 3 numbers whose product is 320, the answer is 4x8x10=320. So the 3 numbers are 4, 8, and 10.
11,8
find two positive numbers whose product is a maximum. 1.) the sum is s.