If that's + 4x2, the answer is 2x(x2 + 2x - 4)
If it's + 7x, the answer is (2x + 3)(5x - 4) If it's - 7x, the answer is (2x - 3)(5x + 4)
(x^2 - 2x + 2)(x^2 + 2x + 2)
(x+6)*(x-4)
The factors are -1(2x + 1)(3x + 4)
2x(x - 4)(x + 4)
The factor is 2x^2(x^2-9)
(2x - 1)(x + 4)
12
If that's + 4x2, the answer is 2x(x2 + 2x - 4)
-4
(2x-4)(x-1) = 0
4 + 32x3 = 4*(1 + 8x3) = 4*(1 + 2x)*(1 - 2x + 4x2) which cannot be factorised further.
(2x - 4)(2x + 3) The key is to look for all the factor pairs of 12.
2(2 + x)
(2x+3)(2x+4)
(x^2 - 2x + 2)(x^2 + 2x + 2)