(6x + 5)(6x + 5) or (6x + 5)2
4x2+20x+25 (2x+5)^2
(x-5i)(x+5i)
x2 + 25 doesn't factor neatly. Applying the quadratic formula, we find two imaginary solutions: Zero plus or minus 5i times the square root of 1.x = 5ix = -5iwhere i is the square root of negative one.
Factor: 9x2 - 25.
(6x + 5)(6x + 5) or (6x + 5)2
(6x+5)(6x-5)
The difference of two squares is quick way to factor polynomials when certain constraints are met: Namely that you have two squares (e.g. 4, 25, 36x2 , 144a6) and one is subtracting from the others (e.g. 25 - 36x2). IF these two constraints are met, then you are able to factor the polynomial by finding the square roots of the squares. sqrt(25)=5 sqrt(36x2) = 6x Therefore 25 - 36x2 = (5+6x)(5-6x) in factored form. In general, given any two squares, a2 and b2, AND they are subtracting, a2 - b2, you can factor them to be (a + b)(a - b).
(6x + 5)(6x - 5)
4n-20n+25
x2 + 10y + 25 doesn't factor neatly. If that was x2 + 10x + 25, it would factor to (x + 5)(x + 5) or (X + 5)2
4x2+20x+25 (2x+5)^2
5(2r + 5)
4x+516x2 + 40x + 25= (4x + 5) (4x + 5)
(4x + 5)(4x + 5)
Factor the polynomial x2 - 10x + 25. Enter each factor as a polynomial in descending order.
(2x - 5)(2x - 5)