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Q: Factor 36x2 plus 60x plus 25?

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(6x + 5)(6x + 5) or (6x + 5)2

4x2+20x+25 (2x+5)^2

(x-5i)(x+5i)

Factor: 9x2 - 25.

x2 + 25 doesn't factor neatly. Applying the quadratic formula, we find two imaginary solutions: Zero plus or minus 5i times the square root of 1.x = 5ix = -5iwhere i is the square root of negative one.

Related questions

(6x + 5)(6x + 5) or (6x + 5)2

(6x+5)(6x-5)

The difference of two squares is quick way to factor polynomials when certain constraints are met: Namely that you have two squares (e.g. 4, 25, 36x2 , 144a6) and one is subtracting from the others (e.g. 25 - 36x2). IF these two constraints are met, then you are able to factor the polynomial by finding the square roots of the squares. sqrt(25)=5 sqrt(36x2) = 6x Therefore 25 - 36x2 = (5+6x)(5-6x) in factored form. In general, given any two squares, a2 and b2, AND they are subtracting, a2 - b2, you can factor them to be (a + b)(a - b).

(6x + 5)(6x - 5)

4n-20n+25

x2 + x + 25 can not be factored.

4x2+20x+25 (2x+5)^2

x2 + 10y + 25 doesn't factor neatly. If that was x2 + 10x + 25, it would factor to (x + 5)(x + 5) or (X + 5)2

5(2r + 5)

4x+516x2 + 40x + 25= (4x + 5) (4x + 5)

(4x + 5)(4x + 5)

That becomes 25y - 25, which factors to 25(y - 1)

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