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There's a chance this was notated incorrectly. It looks like it wants to be some combination of 3x and 2.

9x2 + 12x + 4 = (3x + 2)(3x + 2) or (3x + 2)2

-9x2 - 12x - 4 = -(3x + 2)2

9x2 - 12x + 4 = (3x - 2)2

-9x2 + 12x - 4 = -(3x - 2)2

More answers

If that's + 4, the answer is 4(x - 1)(x - 1)

If the missing signs are pluses, that's (2x + 3)(x + 3)

9x2 - 4 = (3x)2 - 22 = (3x - 2)(3x + 2)

9x2 - 4 = (3x)2 - 22 = (3x + 2)(3x - 2)

3x4(3x3 - 8)

8x2 + 6x - 9 = (2x + 3)*(4x - 3)

Q: What is the factor of 9x2 minus 12x minus 4?

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9x2 + 12x + 4 = 9x2 + 6x + 6x + 4 = 3x(3x + 2) + 2(3x + 2) = (3x + 2)(3x + 2) = (3x + 2)2

x(x + 3)(x - 4)

If the question could more exactly be phrased as, "What is the value of x when 9x2 - 16 = 0", the answer is, x = 4 or -4. This answer can be found by factoring 9x2 - 16 into (3x + 4)(3x - 4) and setting each factor equal to zero.

12x - 4 = 7x - 21 12x -7x = -21 + 4 5x = -17 x = -3.4

If you mean: 9x squared-12x+4 when x = 3 Then it is: (9*3*3)-(12*3)+4 = 49

It is: 122-4*(9*-2) = 216

9x2...I guess that means 9x squared ? The problem: 9x(squared)+12x+4 Here's the answer: (3x+2)(3x+2) or even more simplified: (3x+2) squared

is 9x^2 + 4 prime factor

9x2 + 27x - 36 = 9(x2 + 3x - 4) = 9(x + 4)(x - 1)

(x + 4)(x - 2)(x - 2) or (x + 4)(x - 2)2

(3x + 4)(3x - 4)

Given, 3x2 - 4x = -2 Then, 9x2 - 12x = -6; 9x2 - 12x + 4 = -2 {completing the square} ; 3x - 2 = ±i√2 {sq rt of both sides} ; and 3x = 2 ± i√2. Therefore, x = ⅓(2 ± i√2).