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Factor this expression 9a4 - b2?
9a4-b2=36a-2b=2(18-b) But if you meant 9a^4-b^2 it is not possible to factor
How do you factorising ab xb ac xc?
To factorize the expression abxb + acxc, we first identify the common factors in each term. In this case, the common factors are b in the first term and c in the second term. We then factor out these common factors to get b(a + x) + c(a + x). Finally, we factor out the common binomial factor of (a + x) to get (a + x)(b + c) as the fully factorized expression.
How do you factor the expression 18bc?
2 x 3 x 3 x b x c = 18bc
Factor this expression Check by multiplying factors 2ab-6ac plus 3b 9c?
(2a + 3)(b - 3c)
How do you factor the expression x cubed plus 216?
Use a^3 + b^3 = (a + b)(a^2 - ab + b^2), where a^2 is a squared, a^3 is a cubed. Note that 216 = 6^3.
What is the b factor in the expression x2 plus x-18?
Not sure what the b factor is, but the answer probably is 1, the coefficient of x.
How do you factor the expression a2 4a 4-b2?
(a - b + 2)(a + b + 2)
Factor this expression Check by multiplying factors 3ab-a-3b2 plus b?
(3b - 1)(a - b)
Factor the polynomial expression x2 - 25?
-23
Factor this expression 9a4 - b2?
9a4-b2=36a-2b=2(18-b) But if you meant 9a^4-b^2 it is not possible to factor
How do you factorise a linear?
A linear expression can only have a numeric factor that can be "taken out". The expression will be of the form ax + b where a and b are numbers that have k as their highest common factor (HCF). That is, a = k*c and b = k*d Than being the case, ax + b = kcx + kd = k*(cx + d)
What is the expression as a product of its factor 24BC?
2 x 2 x 2 x 3 x B x C is the expression.
How do you factor 49 plus 14b plus b squared?
a + b + 4 is in its simplest form.
How do you factor a 3 coefficient expression like 4a2 8ab-12b2?
That factors to 4(a - b)(a + 3b)
What is the factor expression of 18bc?
2 x 3 x 3 x b x c
How do you factorising ab xb ac xc?
To factorize the expression abxb + acxc, we first identify the common factors in each term. In this case, the common factors are b in the first term and c in the second term. We then factor out these common factors to get b(a + x) + c(a + x). Finally, we factor out the common binomial factor of (a + x) to get (a + x)(b + c) as the fully factorized expression.
How do you factor this expression completely 9a4 - b2?
You can start by using the formula for the difference of two squares. Actually, after that I don't think you can factor it any further.
