2a3 - 128 = 2*(a3 - 64) = 2*(a -4)*(a2 + 4a + 16)
( a2 ) ( a2+1 )
-18
x2 - 4 is a special expression that is referred to as a difference of squares. Whenever an expression is in the format: a2 - b2 it can be factored out as: (a + b)(a - b) In the case of x2 + 4, that would be: (x + 2)(x - 2)
a2+9a+20 = (a+4)(a+5) when factored
a2 - 4a + 4
If you take the common term 4a out of the expression 16a4 + 4a3, you get 4a(4a3 + a2), making it apparent that if you divide by 4a, the quotient is (4a3 + a2).
2a3 - 128 = 2*(a3 - 64) = 2*(a -4)*(a2 + 4a + 16)
It is: (a+1)(a+3) when factored
a2-5a-14 = (a-7)(a+2) when factored
a3-4a = a(a2-4) when factored
a3 - 2a2 + 4a - 8 = a2(a - 2) + 4(a - 2) = (a - 2)(a2 + 4)
(a - 6)(a + 2)
(4a)2 = 42 * a2 = 16a2
That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: -2 plus or minus the square root of 58. a = 5.6157731058863909 a = -9.615773105863909
The expression is faulty because we don't have + or - before 10a. Also have to assume a2 is a2 . Use the standard formula for solving a quadratic = 0, to get two answers p and q. Then the factorization is (a-p)(a-q).
It is "a squared minus eighteen b".