If the coordinates of the three vertices are (xa, ya), xb, yb) and (xc, yc) then the coordinates of the centroid are [(xa+xb+xc)/3, (ya+yb+yc)/3].
Consider the square ABCD whose diagonals, AC and BD, meet at X.AB is parallel to DC and AC intercepts them. Therefore <BAX = <DCX. AB is parallel to DC and BD intercepts them. Therefore <ABX = <CDX. AB = CD. Therefore triangle ABX is congruent to triangle CDX (SAS). So AX = XC ie X is the midpoint of AC and BX = XB ie X is the midpoint of BD. ie the diagonals bisect each other.
Max's yellow Interceptor was a 1974 XA-XC XB sedan
Either they are in the form of a triangle or they are all on the same straight line.If you are given the points just join any two of the points together and, if required, extend the line. If that line goes through the third point then the points are not in a triangle.If you have the coordinates A = (xa, ya), B = (xb, yb) and C = (xc, yc), thenif xa = xb = xc then they are all on the same straight line and so are not in a triangle.otherwise, if (ya - yb)/(xa - xb) = (yb - yc)/(xb - xc) they are on the same straight line and so are not in a triangle. In all other cases, they are.By extension, if the vector AB is a multiple of vector BC then they are in a straight line. Otherwise they are in a triangle.
XL=XC
First I assume that you mean triangle and not traingle. The answer depends on the form in which you have information about the triangle.If the vertices of the triangle are known in terms of their coordinates: if the three vertices are (xa, ya), (xb, yb) and (xc, yc) then the CoG has the coordinates [(xa+xb+xc)/3, (ya+yb+yc)/3)].Otherwise, they CoG is the point where the medians of the triangle meet.
In case of DC: because the frequency of dc current is zero capacitive reactance ( Xc) = 1/2(22/7)fc f= frequency c=capacitence and when Xc=0 this implies that I=0 In case of AC: Xc >0 => I>0
It depends on whether you mean median in terms of statistical data or the line joining a vertex of a triangle to the midpoint of the opposite side. The Statistical Median: If there are n observations where n is odd, then the median is the (n+1)/2 smallest observation. If n is even, then the median is the arithmetical mean of the n/2 and n/2+1 smallest observations. The Coordinate Geometry Median: Given triangle ABC, with A = (xa, ya), B = (xb, yb) and C = (xc, yc), the midpoint, D of BC is [(xb+xc)/2, (yb+yc)/2] and so, the equation of the median AD is (y-ya)/(x-xa) = (2ya-yb-yc)/(2xa-xb-xc)
Just find the midpoint of opposite corners Consider the rectangle with sides of length a and b. The length of a diagonal is then sqrt(a2+b2) The two diagonals cross at the midpoint or where the length of the line from one vertex to the center is one half of a diagonal or (0.5)[sqrt(a2+b2)]. 1- Consider you have Point A(XA,YA) corresponding to the upper left coordinate of the rectangle and you have Point B(XB, YB) corresponding to the lower right coordinate of the rectangle, then, coordinates of the center Point C (XC, YC) is calculated: XC = XA + (XB-XA)/2 YC = YA - (YA-XB)/2 2- Consider you have Point A(XA,YA) corresponding to the upper left coordinate of the rectangle and the width (W) and height (H) of the rectangle, then, coordinates of the center Point C (XC, YC) is calculated: XC = XA + (W)/2 YC = YA - (W)/2
In resonance condition xl=xc so that the circuit is pure resistive.so that suporposition theorem is applied for both dc and ac circuits
100/80.6=___
Cross Country... XC