Let the 2 numbers be x and y
then we have x+y = 21
y = 21 - x ......(1)
Also given that xy = 98
plug in y from (1)
x(21-x) = 98
21x - x² = 98
x² - 21x + 98 = 0
x² - 14x - 7x + 98 = 0
x(x-14) - 7(x - 14) = 0
(x-14)(x-7) = 0
x = 14 or x = 7
If x = 14 then y =21-14 = 7
If x=7, then y = 21-7 = 14
So the two numbers are 7 and 14
Let's denote the two numbers as x and y. We have the following system of equations: x + y = 21 and xy = 98. From the first equation, we can express y as y = 21 - x. Substituting this into the second equation gives x(21 - x) = 98. Simplifying, we get a quadratic equation x^2 - 21x + 98 = 0. Solving this equation gives x = 14 and y = 7. Therefore, the two numbers are 14 and 7.
Three and Seven
13 and 5 13+5=18 13x5=65
1.61013 and 17.38987 (approx).
20 and 20.
2 3 5 7 11 Sum: 28 Product: 2310
19
find two positive numbers whose product is a maximum. 1.) the sum is s.
10 and 3
9 and 6
you are a nerd
They are: 4 and -3
8 and 8
8 and 5
The numbers are 18 and 20.
Three and Seven
17 and 3 are two prime numbers whose sum is 20. Their product is 51.
The two numbers are 5 and -6. 5x(-6) = -30 so the product is -30 and 5+(-6) = -1 so the sum is -1