Find two numbers whose sum is 21 and product is 98?

Answer 1

Let the 2 numbers be x and y

then we have x+y = 21

y = 21 - x ......(1)

Also given that xy = 98

plug in y from (1)

x(21-x) = 98

21x - x² = 98

x² - 21x + 98 = 0

x² - 14x - 7x + 98 = 0

x(x-14) - 7(x - 14) = 0

(x-14)(x-7) = 0

x = 14 or x = 7

If x = 14 then y =21-14 = 7

If x=7, then y = 21-7 = 14

So the two numbers are 7 and 14

Answer 2

Let's denote the two numbers as x and y. We have the following system of equations: x + y = 21 and xy = 98. From the first equation, we can express y as y = 21 - x. Substituting this into the second equation gives x(21 - x) = 98. Simplifying, we get a quadratic equation x^2 - 21x + 98 = 0. Solving this equation gives x = 14 and y = 7. Therefore, the two numbers are 14 and 7.