7 x 8 = 58 When you factor that into prime factors: 7 x 2 x 4 7 x 2 x 2 x 2 you get the four prime numbers that equal 56.
The LCM of 4, 8, and 56 is 6. Since 4 and 8 are factors of 56, 56 is the LCM of the set. The answer can be found by dividing the 3 numbers into their prime factors, in this case 4=2x2, 8=2x2x2, and 56=7x2x2x2. The lowest common multiple is the smallest number which has all of these prime factors in. That means it has to have two 2's in (from 4) three 2's in (from 8) and three 2's and a 7 from 56. In this case, all of the prime factors of 4 can be found in 8, and all of the prime factors of 8 are in 56, so the LCM (lowest common multiple) of these 3 is 56.
5,5,7 and 7.
Factors of 56: 1 2 4 7 8 14 28 56 Prime factors of 56: 23and 7
3*3*4
7 x 8 = 58 When you factor that into prime factors: 7 x 2 x 4 7 x 2 x 2 x 2 you get the four prime numbers that equal 56.
2 x 2 x 2 x 7
1, 2, 4, 7, 8, 14, 28, 56 2 and 7 are prime.
3 x 7 x 7 = 147
18.6667
Prime factors of 56 First, what two numbers multiplied give you 56? 7 x 8 Is either of these a prime number?? Yes, 7 is prime. What about 8? What two numbers multiplied together give you 8? 2 x 4 Is either of these a prime number?? Yes, 2 is prime. What about 4? What two numbers multiplied together give you 4? 2 x 2 Is either of these a prime number?? Yes, both are prime. Combining our individual results, the prime factorisation of 56 is 7 x 2 x 2 x 2
7 x 8 = 58 When you factor that into prime factors: 7 x 2 x 4 7 x 2 x 2 x 2 you get the four prime numbers that equal 56.
-1, - 1 , -1 and -56. When multiplied together, they make +56.
1 * 56 = 56 2 * 28 = 56 4 * 14 = 56 7 * 8 = 56 8 * 7 = 56 14 * 4 = 56 28 * 2 = 56 56 * 1 = 56
The LCM of 4, 8, and 56 is 6. Since 4 and 8 are factors of 56, 56 is the LCM of the set. The answer can be found by dividing the 3 numbers into their prime factors, in this case 4=2x2, 8=2x2x2, and 56=7x2x2x2. The lowest common multiple is the smallest number which has all of these prime factors in. That means it has to have two 2's in (from 4) three 2's in (from 8) and three 2's and a 7 from 56. In this case, all of the prime factors of 4 can be found in 8, and all of the prime factors of 8 are in 56, so the LCM (lowest common multiple) of these 3 is 56.
5,5,7 and 7.
40 & 4