While it is possible to factor 3x2 from both of these and get 3x2(4 - 1), it's a lot easier to subtract 3x2 from 12x2 and get 9x2
factor out a 3x 3x(x-3)=3x2-9x
7Improved Answer:8x2-18x+9 = (4x-3)(2x-3)
If that's + 18x + 1, the answer is (9x + 1)(9x + 1) or (9x + 1)2
x3 + 9x2 + 27x + 27 Given the numbers in the equation, we can likely bet on (x + 3) being a factor. Let's try it with artificial division: 3 * 1 = 3 9 - 3 = 6 3 * 6 = 18 27 - 18 = 9 3 * 9 = 27 27 - 27 = 0 Bingo. So let's carry it out in long division:                       x2 + 6x + 9                    _____________________ x + 3 ) x3 + 9x2 + 27x + 27                        x3 + 3x2                                        6x2 + 27x                                        6x2 + 18x                                                                9x + 27                                                                9x + 27                                                                                    0 So we have: x3 + 9x2 + 27x + 27 = (x + 3)(x2 + 6x + 9) Which we can now factor further with relative ease: = (x + 3)(x + 3)(x + 3) = (x + 3)3
6x(3x2 - x + 4)
-3(x + 2)(x + 4)
It has one double solution.
3(x - 3)(x + 3)
Divide all terms by 3 and so x2+18x+81= (x+9)(x+9) when factored
x6 - 27 = (x2 - 3)*(x4 + 3x2 + 9) Danny rocks
3x2-27 is equal to -21.
9x2 - 18x = -3x2 - 2x = -1/3x2 - 2x + 1 = 1 - 1/3(x - 1)2 = 2/3x - 1 = ±√2/3x = 1 ± (1/3)√6)
-3x2 + 16x + 12 = -3x2 + 18x - 2x + 12 = -3x*(x - 6) - 2(x - 6) = -(3x + 2)*(x - 6)
The question contains an expression, not an equation and so there is no solution.
While it is possible to factor 3x2 from both of these and get 3x2(4 - 1), it's a lot easier to subtract 3x2 from 12x2 and get 9x2
factor out a 3x 3x(x-3)=3x2-9x