0
x3 + 9x2 + 27x + 27
Given the numbers in the equation, we can likely bet on (x + 3) being a factor. Let's try it with artificial division:
3 * 1 = 3
9 - 3 = 6
3 * 6 = 18
27 - 18 = 9
3 * 9 = 27
27 - 27 = 0
Bingo. So let's carry it out in long division:
x2 + 6x + 9
_____________________
x + 3 ) x3 + 9x2 + 27x + 27
x3 + 3x2
6x2 + 27x
6x2 + 18x
9x + 27
9x + 27
0
So we have:
x3 + 9x2 + 27x + 27
= (x + 3)(x2 + 6x + 9)
Which we can now factor further with relative ease:
= (x + 3)(x + 3)(x + 3)
= (x + 3)3
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How do you factor 27x3-64?
27X^3 - 64 = 0 add 64 to each side 27X^3 = 64 divide each side by 27 X^3 = 64/27 take cubic root of each side X = cubic root(64/27) easy cubic root X = 4/3 check 27(4/3)^3 - 64 = 0 27(2.37037037) - 64 = 0 64 - 64 = 0 checks
How do you factor the trinomial completely 18x3 29x 3x?
I'm guessing that's 18x3 + 29x2 + 3x. That factors to x(2x + 3)(9x + 1) 18x3 + 29x2 + 3x factor x = x(18x2 + 29x + 3) write 29x as 27x + 2x = x(18x2 + 27x + 2x + 3) group by two and factor each group = x[(18x2 + 27x) + (2x + 3)] = x[9x(2x + 3) + 1(2x + 3)] continue factoring = x(2x + 3)(9x + 1) Or since (18)(3) = 54 and (27)(2) = 54 then write: = x(18x2 + 29x + 3) = x[(18x + 27)/9][(18x + 2)/2] = x(2x + 3)(9x + 1)
What is the greatest common factor for 27 and 54?
Since 27 is a factor of 54, and 27 cannot have a larger factor than itself, the greatest common factor of 27 and 54 is 27.
What is the greatest common factor of 27 and 54?
Since 27 is a factor of 54, it is automatically the GCF of this problem.27. 27*2=54.Since 27 is a factor of 54, it is automatically the GCF of this problem.
What is the least common factor of 27?
There cannot be a least common factor of 27, because there cannot be any form of common factor without two or more numbers to compare. Common factors are factors that the numbers being compared have in common. The least common factor would be the smallest common factor that all the numbers have, which would be 1.
