(5b+1)(3b-2)
You know that 15 only has four factors: 1,3,5, and 15. So the first numbers in the parenthesis are either going to be 1 and 15, or 3 and 5. I would try 3 and 5 first because they are closer together, and the other coefficients in the problem are not super large. So I had (5b )(3b ). Then, I looked at -2. There are two ways to get that: -2 x 1 or -1 x 2. Put one set into the parenthesis, foil it out and see if its right. If not, try the other. That's it!
You can take 7b out of both of those, leaving 3a and 2
Well, honey, the greatest common factor in 21ab and 14b is 7b. You see, 21 can be broken down into 3 x 7, and 14 can be broken down into 2 x 7. And since they both have a b in common, that's your greatest common factor right there. Math made sassy!
The GCF is 7b.
The GCF is 7.
7a 7a * 4 = 28a 7a * 7b = 49ab
You can take 7b out of both of those, leaving 3a and 2
It is: (-5b+2)(b-1) with the help of the quadratic equation formula
b^2 - 7b + 12 = b^2 - 4b - 3b + 12 = b(b -4) -3(b - 4) = (b - 3)(b - 4)
7b
100a2 - 49b2 is the difference of two perfect squares. Therefore, it is equal to the sum times the difference of the roots: (10a + 7b)(10a - 7b)
The question is worded amibiguously. Do you mean 3(7b)-2, or 3(7b-2)? 3(7b) - 2: 2 = 21b 2/21 = b 3(7b -2): 21b - 6 = 0. 21b = 6 b = 6/21 = 2/7.
Well, honey, the greatest common factor in 21ab and 14b is 7b. You see, 21 can be broken down into 3 x 7, and 14 can be broken down into 2 x 7. And since they both have a b in common, that's your greatest common factor right there. Math made sassy!
The GCF is 7b.
The GCF is 7.
(a - 7b)(a + 6b)
No. 7b - 2b = 5b
(-3b - 4)(-2b + 5)