4(16a4 + b2)
4(4a2 - b2) 4(2a + b)(2a - b)
Assuming the missing sign is "minus" then you have the difference between two squares. This is solved as (x + y)(x - y). In your example x = 4a and y = 2b so the factorisation is (4a + 2b)(4a - 2b) or more completely: (4)(2a + b)(2a - b).
2a + 4b + 8c = 2(a + 2b + 4c) You could also continue by factoring the inside of the parentheses a bit: 2a + 4b + 8c = 2(a + 2b + 4c) = 2(a + 2[b + 2c])
They are 1, 2, 3, 4, 6, 9, 12, 18, 36,1a, 2a, 3a, 4a, 6a, 9a, 12a, 18a, 36a,1b, 2b, 3b, 4b, 6b, 9b, 12b, 18b, 36b,1a2, 2a2, 3a2, 4a2, 6a2, 9a2, 12a2, 18a2, 36a2,1ab, 2ab, 3ab, 4ab, 6ab, 9ab, 12ab, 18ab, 36ab,1b2, 2b2, 3b2, 4b2, 6b2, 9b2, 12b2, 18b2, 36b2.
4(16a4 + b2)
(2b - 1)(2b + 1)
4b2-16 =4(b2-4) =4(b+2)(b-2)
4(4a2 - b2) 4(2a + b)(2a - b)
12b3
ok i need help with this someone help
8/12 = 4/3b8/12 = 4 x b/33x8/12 = 4xb24/12 = 4b2 = 4b2/4 = 4b/4b = 2/4b = 1/2
C. 12b3
Assuming the missing sign is "minus" then you have the difference between two squares. This is solved as (x + y)(x - y). In your example x = 4a and y = 2b so the factorisation is (4a + 2b)(4a - 2b) or more completely: (4)(2a + b)(2a - b).
Factor them. 2 x 2 x b x b = 4b2 2 x 3 x b x b x b = 6b3 Combine the factors, eliminating duplicates. 2 x 2 x 3 x b x b x b = 12b3, the LCM
Proper factors do not include one and the number itself. The only one left is 2.
Area = ½base x height = 18; h = 4b, so b/2 x 4b = 18 ie 4b2 = 36making b2 = 9 and b = 3 inches