Not sure about the greatest commom factor, but the greatest common factor is b.
4(16a4 + b2)
4(4a2 - b2) 4(2a + b)(2a - b)
Assuming the missing sign is "minus" then you have the difference between two squares. This is solved as (x + y)(x - y). In your example x = 4a and y = 2b so the factorisation is (4a + 2b)(4a - 2b) or more completely: (4)(2a + b)(2a - b).
2a + 4b + 8c = 2(a + 2b + 4c) You could also continue by factoring the inside of the parentheses a bit: 2a + 4b + 8c = 2(a + 2b + 4c) = 2(a + 2[b + 2c])
They are 1, 2, 3, 4, 6, 9, 12, 18, 36,1a, 2a, 3a, 4a, 6a, 9a, 12a, 18a, 36a,1b, 2b, 3b, 4b, 6b, 9b, 12b, 18b, 36b,1a2, 2a2, 3a2, 4a2, 6a2, 9a2, 12a2, 18a2, 36a2,1ab, 2ab, 3ab, 4ab, 6ab, 9ab, 12ab, 18ab, 36ab,1b2, 2b2, 3b2, 4b2, 6b2, 9b2, 12b2, 18b2, 36b2.
4(16a4 + b2)
(2b - 1)(2b + 1)
4b2-16 =4(b2-4) =4(b+2)(b-2)
4(4a2 - b2) 4(2a + b)(2a - b)
12b3
To solve the expression (-8a^2 + 4ab + 4b^2), you can look for common factors or factor it if possible. In this case, notice that the expression can be factored as (-4(2a^2 - ab - b^2)). You can further factor (2a^2 - ab - b^2) if it can be expressed as a product of binomials, but in its current form, this is a simplified version.
ok i need help with this someone help
8/12 = 4/3b8/12 = 4 x b/33x8/12 = 4xb24/12 = 4b2 = 4b2/4 = 4b/4b = 2/4b = 1/2
C. 12b3
Assuming the missing sign is "minus" then you have the difference between two squares. This is solved as (x + y)(x - y). In your example x = 4a and y = 2b so the factorisation is (4a + 2b)(4a - 2b) or more completely: (4)(2a + b)(2a - b).
To solve the expression (16a^2 - 4b^2), you can factor it using the difference of squares formula, which states that (x^2 - y^2 = (x - y)(x + y)). Here, you can rewrite (16a^2) as ((4a)^2) and (4b^2) as ((2b)^2). Thus, the expression factors to ((4a - 2b)(4a + 2b)).
Factor them. 2 x 2 x b x b = 4b2 2 x 3 x b x b x b = 6b3 Combine the factors, eliminating duplicates. 2 x 2 x 3 x b x b x b = 12b3, the LCM