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How do you factor 64a4 plus 4b2?
4(16a4 + b2)
How do you factor 16a2-4b2?
4(4a2 - b2) 4(2a + b)(2a - b)
How do you factor 16a2 4b2?
Assuming the missing sign is "minus" then you have the difference between two squares. This is solved as (x + y)(x - y). In your example x = 4a and y = 2b so the factorisation is (4a + 2b)(4a - 2b) or more completely: (4)(2a + b)(2a - b).
How do you factorise 2a plus 4b plus 8c?
2a + 4b + 8c = 2(a + 2b + 4c) You could also continue by factoring the inside of the parentheses a bit: 2a + 4b + 8c = 2(a + 2b + 4c) = 2(a + 2[b + 2c])
What are all the factors of the monomial 6ab to the 2nd power?
They are 1, 2, 3, 4, 6, 9, 12, 18, 36,1a, 2a, 3a, 4a, 6a, 9a, 12a, 18a, 36a,1b, 2b, 3b, 4b, 6b, 9b, 12b, 18b, 36b,1a2, 2a2, 3a2, 4a2, 6a2, 9a2, 12a2, 18a2, 36a2,1ab, 2ab, 3ab, 4ab, 6ab, 9ab, 12ab, 18ab, 36ab,1b2, 2b2, 3b2, 4b2, 6b2, 9b2, 12b2, 18b2, 36b2.
How do you factor 64a4 plus 4b2?
4(16a4 + b2)
How do you Factor 4b2 - 1?
(2b - 1)(2b + 1)
What is the factor of 4b2-16?
4b2-16 =4(b2-4) =4(b+2)(b-2)
How do you factor 16a2-4b2?
4(4a2 - b2) 4(2a + b)(2a - b)
What is the LCM of 4b2 and 6b3?
12b3
What is the answer to 3a b2 b3 4b2 a 5a?
ok i need help with this someone help
What is the answer to 8 over 12 divided by b equals 4 over 3?
8/12 = 4/3b8/12 = 4 x b/33x8/12 = 4xb24/12 = 4b2 = 4b2/4 = 4b/4b = 2/4b = 1/2
What is the LCM of 4b2 and 6b3 A 2b2 B 12b2 C 12b3 D 24b3?
C. 12b3
How do you factor 16a2 4b2?
Assuming the missing sign is "minus" then you have the difference between two squares. This is solved as (x + y)(x - y). In your example x = 4a and y = 2b so the factorisation is (4a + 2b)(4a - 2b) or more completely: (4)(2a + b)(2a - b).
How do you solve 16a2-4b2?
To solve the expression (16a^2 - 4b^2), you can factor it using the difference of squares formula, which states that (x^2 - y^2 = (x - y)(x + y)). Here, you can rewrite (16a^2) as ((4a)^2) and (4b^2) as ((2b)^2). Thus, the expression factors to ((4a - 2b)(4a + 2b)).
What the LCM of 63 and 76?
Factor them. 2 x 2 x b x b = 4b2 2 x 3 x b x b x b = 6b3 Combine the factors, eliminating duplicates. 2 x 2 x 3 x b x b x b = 12b3, the LCM
What are the proper factors of 4?
Proper factors do not include one and the number itself. The only one left is 2.
