(2x + 7)(x - 2)
It doesn't factor evenly if it were x**2-11x+10: x**2-11x+10 = (x-1)(x-10)
The "difference of squares" has a formula. (11x + 1)(11x - 1)
x2 -11x-12= (x-12)(x+1)
(2x2 - 1)(2x2 - 1) or (2x2 - 1)2
(2x - 7)(x - 2)
2x2 + 11x + 12 = 2x2 + 3x + 8x + 12 = x*(2x + 3) + 4*(2x + 3) = (2x + 3)*(x + 4)
If you mean: 2x2+11x+15 then it is (2x+5)(x+3) when factored
2x2 + 11x + 15 = (x + 3)(2x + 5).
2x2 + 15 = 11x ? Can be only for some values of x.2x2 + 15 = 11x subtract 11x to both sides2x2 - 11x + 15 = 0(2x - 5)(x - 3) = 02x - 5 = 0 or x - 3 = 0x = 5/2 or x = 3
9x2+11x-14 = (9x-7)(x+2) when factored with the help of the quadratic equation formula.
no false
17x2-11x+2 = 2x2 Subtract 2x2 from both sides: 15x2-11x+2 = 0 Factorise: (3x-1)(5x-2) = 0 Solution: x =1/3 or x = 2/5
If you mean: 2x2-11x+5 then it is (2x-1)(x-5) when factored
You have to experiment with different factors of 2, and different factors of 15. In this case, 2x2 - 11x + 15 = (2x - 5) (x - 3)
(x-2)(2x+7)
(2x + 7)(x - 2)