Well, well, well, look who's trying to factor a quadratic equation! To factor 2x^2 + 11x + 14, you need to find two numbers that multiply to 28 (2*14) and add up to 11. Those numbers are 2 and 14. So, the factored form is (2x + 7)(x + 2). Voila!
To factor the quadratic expression 2x^2 - 11x + 14, we need to find two numbers that multiply to the product of the coefficient of the x^2 term (2) and the constant term (14), which is 28, and add up to the coefficient of the x term (-11). The two numbers are -7 and -4. Therefore, we can rewrite the expression as 2x^2 - 7x - 4x + 14. Factoring by grouping, we get 2x(x - 7) - 2(x - 7), which simplifies to (2x - 2)(x - 7) or 2(x - 1)(x - 7).
(2x + 7)(x - 2)
It doesn't factor evenly if it were x**2-11x+10: x**2-11x+10 = (x-1)(x-10)
The "difference of squares" has a formula. (11x + 1)(11x - 1)
x2 -11x-12= (x-12)(x+1)
(2x2 - 1)(2x2 - 1) or (2x2 - 1)2
(2x - 7)(x - 2)
2x2 + 11x + 12 = 2x2 + 3x + 8x + 12 = x*(2x + 3) + 4*(2x + 3) = (2x + 3)*(x + 4)
If you mean: 2x2+11x+15 then it is (2x+5)(x+3) when factored
2x2 + 11x + 15 = (x + 3)(2x + 5).
2x2 + 15 = 11x ? Can be only for some values of x.2x2 + 15 = 11x subtract 11x to both sides2x2 - 11x + 15 = 0(2x - 5)(x - 3) = 02x - 5 = 0 or x - 3 = 0x = 5/2 or x = 3
9x2+11x-14 = (9x-7)(x+2) when factored with the help of the quadratic equation formula.
no false
17x2-11x+2 = 2x2 Subtract 2x2 from both sides: 15x2-11x+2 = 0 Factorise: (3x-1)(5x-2) = 0 Solution: x =1/3 or x = 2/5
If you mean: 2x2-11x+5 then it is (2x-1)(x-5) when factored
You have to experiment with different factors of 2, and different factors of 15. In this case, 2x2 - 11x + 15 = (2x - 5) (x - 3)
(x-2)(2x+7)
(2x + 7)(x - 2)