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How do you factor 2x squared minus 11x plus 15?
You have to experiment with different factors of 2, and different factors of 15. In this case, 2x2 - 11x + 15 = (2x - 5) (x - 3)
What is the solution set of 2x2 x equals 15?
What is the solution set of 2x2 + x = 15
What is 6 plus 11x -60?
6 + 11x - 60 =6 - 60 + 11x = -54 + 11x = 11x -54
What is 1 plus 11x?
1 + 11x =1 + 11x (this is the simplest solution you can make with available information)
How do you solve 12 x - 5 equals 11 x plus 5?
12x - 5 = 11x + 5(1) add 5 to both sides:12x - 5 + 5 = 11x + 5 + 512x = 11x + 10(2) next subtract 11x from both sides:12x - 11x = 11x - 11x + 10x = 10
What is 2x2 plus 11x plus 15?
2x2 + 11x + 15 = (x + 3)(2x + 5).
2x2 plus 15 equals 11x?
2x2 + 15 = 11x ? Can be only for some values of x.2x2 + 15 = 11x subtract 11x to both sides2x2 - 11x + 15 = 0(2x - 5)(x - 3) = 02x - 5 = 0 or x - 3 = 0x = 5/2 or x = 3
How do you factor 2x squared minus 11x plus 15?
You have to experiment with different factors of 2, and different factors of 15. In this case, 2x2 - 11x + 15 = (2x - 5) (x - 3)
How do you factor 2x2 11x 14'?
If that's +11x + 14, the answer is (x + 2)(2x + 7)
2x2 - 11x - 1 equals 0?
no false
What is the solution for 17x2-11x plus 2 equals 2x2?
17x2-11x+2 = 2x2 Subtract 2x2 from both sides: 15x2-11x+2 = 0 Factorise: (3x-1)(5x-2) = 0 Solution: x =1/3 or x = 2/5
What is 2x2-11x5 factored?
If you mean: 2x2-11x+5 then it is (2x-1)(x-5) when factored
How do you factor 2x squared plus 11x plus 12?
2x2 + 11x + 12 = 2x2 + 3x + 8x + 12 = x*(2x + 3) + 4*(2x + 3) = (2x + 3)*(x + 4)
Factoring 2x2-11x plus 14?
(2x - 7)(x - 2)
Twice the square of an integer is five less than eleven times the integer The integer is?
2x2 = 11x - 5 2x2 - 11x + 5 = 0 (x - 5)(2x - 1) = 0 x = 5 or 0.5 Check: 2 x 25 = 55 - 5 ok 2 x 0.25 = 5.5 - 5 ok The integer is 5.
2x2 plus 11x plus 5 equals 0?
x = -1/2 or -5 2x2 + 11x + 5 = 0 ⇒ (2x + 1)(x + 5) = 0 ⇒ (2x + 1) = 0 → x = -1/2 or (x + 5) = 0 → x = -5
What is 2x3 plus 11x equals 6x?
your equation is this... 2x3 + 11x = 6x 2x3 + 5x = 0 x(2x2 + 5) = 0 x = 0 and (5/2)i and -(5/2)i
