no false
17x2-11x+2 = 2x2 Subtract 2x2 from both sides: 15x2-11x+2 = 0 Factorise: (3x-1)(5x-2) = 0 Solution: x =1/3 or x = 2/5
x = -1/2 or -5 2x2 + 11x + 5 = 0 ⇒ (2x + 1)(x + 5) = 0 ⇒ (2x + 1) = 0 → x = -1/2 or (x + 5) = 0 → x = -5
11x(2x - 1) = 0 so either 11x = 0 or x = ½
x2 = 11x - 10 ∴ x2 - 11x + 10 = 0 ∴ (x - 10)(x - 1) = 0 ∴ x ∈ {1, 10}
x2 = -11x - 10 x2 + 11x + 10 = 0 (x + 1)(x + 10) = 0
To solve for x: x2 = 11x - 10 x2 - 11x = -10 x2 - 11x + 10 =0 (x - 1)(x - 10) = 0 x = {1, 10)
21
If: 2x2-3x+1 = 0 Then: x = 1 or x = 1/2
If you mean: 2x2-11x+5 then it is (2x-1)(x-5) when factored
2x2-x-3 = 0= 4 - x - 3 = 0= 1 - x = 0= 1 = xTherefore x = 1
(-2,-1)
2x2+1x-3=0 4+x-3=0 x+1+0 x=-1 is your final answer