(4x + 5)(3x - 7)
28 4 x 7 2x2 7 = 2x2x7
(x - 6)(x - 7)
224 8 x 28 (2x4) x (4x7) (2 x (2x2)) x ((2x2) x 7) Since 2 and 7 are prime numbers, the factor tree is complete.
(2x + 7)(x - 2)
2x2 - 13x - 7 = (2x + 1)(x - 7)
2x2+13x+15 = (2x+3)(x+5)
The expression cannot be factorised.
This is a quadratic equation question which will have two answers: 2x2+42 = x2+13x 2x2-x2-13x+42 = 0 x2-13x+42 = 0 Factorising the equation gives you: (x-6)(x-7) = 0 Therefore: x = 6 or x = 7
2x2 + 13x - 7 = zero(2x - 1 )( x + 7 ) = zero2x - 1 = zerox = 1/2x + 7 = zerox = -7
(x -3)(2x2 + 3x - 4)
(3x + 7)(2x - 9)
(4x + 5)(3x - 7)
(x + 1)(2x - 7)
(x - 6)(x - 7)
(4x + 5)(3x - 7)
28 4 x 7 2x2 7 = 2x2x7