2x2 - 13x - 7 = (2x + 1)(x - 7)
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2x2 + 13x - 7 = zero(2x - 1 )( x + 7 ) = zero2x - 1 = zerox = 1/2x + 7 = zerox = -7
6x2 - 13x - 63 = 6x2 + 14x - 27x - 63 = 2x(3x + 7) - 9(3x + 7) = (3x + 7)(2x - 9)
(x-2)(2x+7)
13x-14 or 13x+(-14)
2x 2+13x+15 = (2x + )(x + ) since the only way to get 2 is 1 times 2. The missing numbers must be filled with with 1 and 15 or 3 and 5 in some order, so by trial and error we get. 2x 2+13x+15 = (2x + 3 )(x + 5 )