2x2 + 13x - 7 = zero(2x - 1 )( x + 7 ) = zero2x - 1 = zerox = 1/2x + 7 = zerox = -7
6x2 - 13x - 63 = 6x2 + 14x - 27x - 63 = 2x(3x + 7) - 9(3x + 7) = (3x + 7)(2x - 9)
(x-2)(2x+7)
13x-14 or 13x+(-14)
2x 2+13x+15 = (2x + )(x + ) since the only way to get 2 is 1 times 2. The missing numbers must be filled with with 1 and 15 or 3 and 5 in some order, so by trial and error we get. 2x 2+13x+15 = (2x + 3 )(x + 5 )
(x + 7)(2x - 1)
2x2+13x+15 = (2x+3)(x+5)
The expression cannot be factorised.
This is a quadratic equation question which will have two answers: 2x2+42 = x2+13x 2x2-x2-13x+42 = 0 x2-13x+42 = 0 Factorising the equation gives you: (x-6)(x-7) = 0 Therefore: x = 6 or x = 7
2x2 + 13x - 7 = zero(2x - 1 )( x + 7 ) = zero2x - 1 = zerox = 1/2x + 7 = zerox = -7
(x -3)(2x2 + 3x - 4)
(3x + 7)(2x - 9)
(4x + 5)(3x - 7)
(x + 1)(2x - 7)
(x - 6)(x - 7)
(4x + 5)(3x - 7)
28 4 x 7 2x2 7 = 2x2x7