While it is possible to factor 3x2 from both of these and get 3x2(4 - 1), it's a lot easier to subtract 3x2 from 12x2 and get 9x2
4x2(4x3 + 3)
12x ^2 -32x-12
(x + 7)(2x - 1)
x4 - 4x3 - 12x2 -32x + 64 (x - 4)(x + 2)(x + 2)(x - 4)
(4x + 5)(3x - 7)
12x2+13x-35 = (4x-5)(3x+7) 12x2 + 13x- 35 let's find two factors of -420 (12*-35) whose sum is 13, which are 28 and -15 (12x + 28)(12x - 15) now simplify by 4 and 3 (3x + 7)(4x - 5)
12x2-x-35 = (4x-7)(3x+5)
Factor: x3 - 12x2 + 35x 1. Factor out a x: x(x2 - 12x + 35). 2. Factor x2 - 12x + 35 which is (x-5)(x-7). 3. Answer: x(x-5)(x-7).
12x2-8x
x2 + 12x2 + 35 = 13x2 + 35 which cannot be factorised in any sensible way.
While it is possible to factor 3x2 from both of these and get 3x2(4 - 1), it's a lot easier to subtract 3x2 from 12x2 and get 9x2
12x2-23x+10 = (3x-2)(4x-5) when factored
3x(4x - 3)
2x2 - 13x - 7 = (2x + 1)(x - 7)
Factor out an X X(X^2 - 12X + 35) factor quadratic equation X(X - 7)(X - 5) ------------------- fully factored
(4x - 7)(3x + 5)