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If that's + 49y2, the answer is (9x - 7y)(9x - 7y) or (9x - 7y)2
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How do you factor 81x2 126xy 49y2?
If that's + 49y2, the answer is (9x - 7y)(9x - 7y) or (9x - 7y)2
What are the factors of 64x3 plus 343y3?
(4x + 7y)(16x2 - 28xy + 49y2)
A proper factor is a factor?
a proper factor is a factor.
What is a factor bug?
a factor bug is a factor
What is a composite factor?
A composite factor is a factor that is a composite number, as opposed to a prime factor which is a factor that is a prime number.
How do you factor 81x2 126xy 49y2?
If that's + 49y2, the answer is (9x - 7y)(9x - 7y) or (9x - 7y)2
Factor 4x2 plus 28xy plus 49y2?
4x^(2) + 28xy + 49y^(2) -> (2x)^(2) + 28xy + (7y)^2 Split into brackets ( 2x + 7y)(2x + 7y) If you applyuFOIL you will find toy come to '28xy'. The clue to this problem is to note that '4' ^ '49' are both squared numbers.
How do you factor 49y squared minus z squared?
This is a difference of two sqaures. 49y2 - z2 = (7y - z)(7y + z)
Is 49y2-35 plus 6 a trinomial square?
No.
What is 4x plus 7y squared?
16x2+56xy+49y2
Is 49y2-144 factorable?
(7y-12)(7y+12)
What are the factors of 64x3 plus 343y3?
(4x + 7y)(16x2 - 28xy + 49y2)
How do you factor the perfect trinomial?
Do you mean some thing like 4x2 - 28xy + 49y2 ? notice 4x2 = (2x)2 and 49y2 = either (7y)2 or (-7y)2 (1st and last terms must be squares) and the middle term is 2(2x)(-7y) (2 times sq root of 1st times sq root of last) Once the pattern is recognized: (sq root 1st + sqroot 2nd)2 or (sq root 1st - sqroot 2nd)2 depending on if middle term is positive or negative. So, back to my example: 4x2 - 28xy + 49y2 = (2x - 7y)2 because middle is negative. Simpler example factor x2 + 6x + 9. 1st and last are both squares sq root of 9 = 3 3 times 2 = 6 that fits the middle so x2 + 6x + 9 = (x + 3)2
Is this trinomial a trinomial square 49y2 - 35y plus 6?
Factors are (7y - 3)(7y - 2) so it's not a perfect square.
What Is 25x Quared Minus 49y Squared Show Steps?
25x2-49y2 is the difference of two squares and can be factored as:- (5x-7y)(5x+7y)
How do you factor 125x3 plus 343y3?
125x3+343y3 can also be written (5x)3+(7y)3. It helps to rewrite the constants like this because there is a general factoring rule: a3+b3 = (a+b)(a2-ab+b2). In this example, the a is 5x and the b is 7y. Plug in and get (5x+7y)(25x2-35xy+49y2).
What is 27x cubed plus 343y cubed factored?
In order to factor the sum of the cubes, we need to use this form a³ + b³ = (a + b)(a² - ab + b²). Let a³ = 27x³ and b³ = 343y³. Then, a = 3x and b = 7y. Perform substitution of these terms for the form, and we obtain: 27x3 + 343y3 = (3x + 7y)(9x2 - 21xy + 49y2)
