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Suppose the trinomial is x2 + Bx + C

You need to find a factor pair of C whose sum is B.

If the factors are p and q (that is, pq = C and p+q = B), then the trinomial can be factorised as (x + p)*(x + q).

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Q: How do you factor a trinomial with a leading coefficient is equal to 1?
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Which part of the trinomial will equal the sum of p and q?

the coefficient of the x-term


What is the difference between a coefficient and a factor?

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How do factor a trinomial expression with a leading coefficient not equal to 1?

To factor a trinomial in the form ax2 + bx + c, where a does not equal 1, the easiest process is called "factoring by grouping". To factor by grouping, you must change the trinomial into an equivalent tetranomial by rewriting the middle term (bx) as the sum of two terms. There is a specific way to do this, as demonstrated in the example.Take the quadratic trinomial 5x2 + 11x + 21. Find the product of a and c, or 5*2 = 10.2. Find factors of ac that when added together give you b, in this case 10 and 1.3. Rewrite the middle term as the sum of the two factors (5x2 + 10x + x + 2).4. Group terms with common factors and factor these groups.5x2 + x + 10x + 2x(5x + 1) + 2(5x + 1)5. Factor the binomial in the parentheses out of the whole polynomial, leaving you with the product of two binomials. 5x2 + 11x + 2 = (x + 2)(5x + 1)Notes:1. The same process is done if there are any minus signs in the trinomial, just be careful when factoring out a negative from a positive or vice versa.2. If you have a tetranomial on its own, you can skip the rewriting process and just factor the whole polynomial by grouping from the start.3. As in factoring any polynomial, always factor out the GCF first, then factor the remaining polynomial if necessary.4. Always look for patterns, like the difference of squares or square of a binomial, while factoring. It will save a lot of time.


81x2 - 72x plus 16 is a perfect square trinomial true or false?

If a trinomial is a perfect square, then the discriminant will equal 0. The discriminant is equal to B^2-4AC. The variables come from the standard form of a quadratic which is Ax^2+Bx+C In this problem, A=81, B=-72, and C=16 so the discriminant is: (-72)^2-4(81)(16)=5,184-5,184=0 so this is a perfect square trinomial. To factor, notice that 81=9^2 and 16=4^2, so 81x^2=(9x)^2. We can then factor the trinomial into (9x+4)(9x-4)


What is the difference in finding the m and n when factoring a polynomial with a leading coefficient that does not equal one?

The difference depends on what m and n equal. If they are both variable then it dpends on what the equations are for each variable.


Relationship between coefficient lift and coefficient drag?

For cylinders coefficient of lift is approximately half of coefficient of drag while they are equal for Aerofoils.


Which part of the trinomial will equal the product of p and q?

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How do you factor polynomials into binomials and trinomials?

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How do you factor q2-7q plus 12?

1. When factoring first always look for a GCF (greatest common factor). If each term has a greatest common factor, factor it out in from using parenthesis first. This problem does not have a GCF. 2. Next, since this is a trinomial, many times we can factor it down using backwards FOIL (First, Outter, Inner, Last). 3. To do this always put down two sets of parenthesis. (we do this because we are looking to factor into two binomials) ( )( ) 4. Next we complete the fist term in each set of parenthesis. The first term is simply going to be the variable we are using in the problem. In this problem the variable is q. (q )(q ) 5. Then find the factors of the last term (+12) in which the sum is equal to the coefficient of the middle term (-7). These factors are -3 and -4. 6. Complete the factoring by putting these factors into the second part of the parenthesis. (q - 3)(q - 4) * If you want to make sure you are correct, multiply you answer out and see if you get the same trinomial you started with.