(x - 3)(x + 3)(x2 + 9)
1,2,3,4,6,8,9,12,18,24,36,72 factor of 72 1,3,9,27,and 81 is factor of 81
A factor = a number which can be divided into the given number with no remainder Yes. It's the only factor of 81 (apart from 9, 27 and 81 itself).
81 27,3 9,3,3 3,3,3,3
The greatest common factor of 16 72 and 81 is 1.
The factors of 81 are 1, 3, 9, 27, and 81. The factors of 243 are 1, 3, 9, 27, 81, and 243. The common factors of 81 and 243 are 1, 3, 9, 27, and 81. Therefore, the least common factor (the smallest common factor) is 1.
x = plus or minus two thirds
(81 - m2) = (9 - m)(9 + m)
x2-81 = (x-9)(x+9)
92=81 2-81= -79
I believe it is prime as you have written it. change the end to + 81 and it factors as (2x - 1)(x-9)(x+9)
(9 - 5u)(9 + 5u)
81
(2x - 9)(2x +9)
0.3333
(x - 9)(x^2 + 9x + 81)
81
81