1,2,3,4,6,8,9,12,18,24,36,72 factor of 72 1,3,9,27,and 81 is factor of 81
To find the highest common factor (HCF) of 81, 243, and 1215, we first need to find the prime factorization of each number. The prime factorization of 81 is 3^4, 243 is 3^5, and 1215 is 3^5 * 5. To find the HCF, we look for the highest power of each prime factor that appears in all the numbers. In this case, the highest power of 3 that appears in all three numbers is 3^4, so the HCF of 81, 243, and 1215 is 81.
A factor = a number which can be divided into the given number with no remainder Yes. It's the only factor of 81 (apart from 9, 27 and 81 itself).
81 27,3 9,3,3 3,3,3,3
The greatest common factor of 16 72 and 81 is 1.
x = plus or minus two thirds
(81 - m2) = (9 - m)(9 + m)
x2-81 = (x-9)(x+9)
92=81 2-81= -79
I believe it is prime as you have written it. change the end to + 81 and it factors as (2x - 1)(x-9)(x+9)
(9 - 5u)(9 + 5u)
81
0.3333
81
81
(x - 9)(x^2 + 9x + 81)
81 minus 86 = -5