Euclidean Algorithm
It is not necessary to actually list the factors of all numbers to get the GCF for only two numbers. You can use the Euclidean algorithm.
(1) Divide the larger number by the smaller one.
(2) If there is no remainder, the GCF is the same as the smaller number.
(3) Repeat step 1 with the smaller number and the remainder.
Example:
GCF of 51 and 85.
85/51 = 1 R 34
51/34 = 1 R 17
34/17 = 2 R 0<== By step 2, we are done. Our answer is 17.
Lets try one that doesn't reduce -- GCF(17,39)
39/17 = 2 R 5
17/5 = 3 R 2
5/2 = 2 R 1
2/1 = 2 R 0, so our answer, the GCF, is 1.
If you have two numbers A and B, and A > B, then GCF(A, B) = (A-B, B) Thus the problem of finding the GCF of A and B has been reduced to finding the GCF of B and a smaller number, A-B. This process can be continued until the two numbers are the same: and that number is the GCF.
The first step of finding the GCF is to split the numbers into their prime factors. For instance, if I wanted to find the GCF of 30 and 105, I would split these up into: 30 = 2x3x5 105 = 3x5x7 The next step would be to identify any common prime factors. In this case both numbers have 3 and 5 as prime factors, so these would be the ones we use. To find the GCF, you simply multiply these two numbers together: 3x5 = 15 So 15 would be the GCF in that case.
The greatest common factor (GCF) of two numbers is the largest number that divides both numbers without leaving a remainder. To find the GCF of 180 and 1750, you can use the prime factorization method. The prime factorization of 180 is 2^2 * 3^2 * 5, and the prime factorization of 1750 is 2 * 5^3 * 7. To find the GCF, you take the common prime factors with the lowest exponent, which in this case is 2 * 5 = 10. Therefore, the GCF of 180 and 1750 is 10.
It's the same as gcf(gcf(75, 100), 175). In other words, you can first use Euclid's algorithm to find the gcf of 75 and 100; then you can calculate the gcf of the result with 175. To help you get started, by Euclid's algorithm, the gcf of 75 and 100 is the same as the gcf of 75 and 25 (where 25 is the remnainder of the division of 100 / 75).
It's not necessary. Since 12 is a factor of 72, it is automatically the GCF.
Gcf you use when you are finding the greatest factor for the numbers. Lcm you use when you are finding the smallest multiple in the numbers factors
If you have two numbers A and B, and A > B, then GCF(A, B) = (A-B, B) Thus the problem of finding the GCF of A and B has been reduced to finding the GCF of B and a smaller number, A-B. This process can be continued until the two numbers are the same: and that number is the GCF.
The GCF of 50 and 54 is 2. Use whatever method you wish.
It doesn't matter what method you use, you need at least two numbers to find a GCF.
The gcf is 3.
Finding the LCM will help you add and subtract fractions. Finding the GCF will help you reduce fractions.
You need at least two numbers to find a GCF, whichever method you use.
im not sure how to answer it
It works out as 17
Methods aren't necessary. The only common factor (which makes it the GCF) of 16 and 35 is 1.
If you need to determine the greatest common factor (gcf), there are several methods you can use. By definition it is the largest number that divides all numbers in question.1st method-------------You typically factor each number in its unique prime factorization.You then use only those prime factors that occur in all of these numbers and multiply them.2nd method-------------Another way to compute it is as follows.First determine the gcf of two numbers as follows:gcf(x,y) = gcf(x-y,y) if x>y,gcf(x,y) = gcf(y,y-x) if y>x.gcf(x,y) = x if x=y.Repeat this schema until you found it (using the third line).Then use this to compute the gcf between this found gcf and another number, and so on, i.e.,gcf(x,y,z) = gcf(gcf(x,y),z).Example:----------gcf(60,42)1st method:-------------60 = 2 x 2 x 3 x 542 = 2 x 3 x 7So gcf(60,42) = 2 x 3 = 62nd method:--------------(60,42) = (18,42) = (18, 24) = (18, 6) = (12,6) = (6,6) = 6Exercise.Prove that the second method always gives the same answer as the first method.
By finding the lowest common multiple of the denominators.