22
4s2 - 9 can be expressed by using the identity: a2 - b2 = (a-b)(a+b) Therefore, 4s2 - 9 = (2s)2 - 32 = (2s-3)(2s+3)
1/x2 or x-2
12
To write (2) to the (9)th power in standard form, you calculate (2^9), which equals (512). Thus, in standard form, it is simply written as (512).
2 x 102 or 200
To use five 2s to make 3, you can employ a mathematical operation like exponentiation. One way to achieve this is by arranging the 2s as follows: (2^2) - (2/2) = 3. This expression involves raising 2 to the power of 2 (which equals 4) and then subtracting the result of dividing 2 by 2 from it, resulting in 3.
For the formation of sodium fluoride, sodium (Na) will transfer one electron to fluorine (F) to achieve a stable electron configuration. The electron configuration for sodium is [Ne] 3s^1, and for fluorine, it is [He] 2s^2 2p^5. After transfer, sodium forms the Na+ cation with an electron configuration of [Ne], and fluorine forms the F- anion with an electron configuration of [He] 2s^2 2p^6.
Two to the third power can be written in several ways, including (2^3), which represents the base 2 raised to the exponent 3. It can also be expressed as (2 \times 2 \times 2), showing the multiplication of three 2s. Additionally, the numerical result of (2^3) is 8, so it can simply be represented as 8.
If p = 2s + 5, then s = (p-5)/2 or 1/2 (p-5) --- p = 2s +5 p-5 = 2s (p-5)/2 = s
Well, honey, if you want to make five 2s equal five, all you gotta do is write it as 2 + 2 + 2/2 = 5. Simple math, darling. Just divide one of those pesky 2s by 2 and voila, you've got yourself a nice little equation that adds up to 5.
You can use three 2s to make 26 as follows (2x2)! + 2 = 26 So you can simply make 26 with five 2s as (2x2!) + 2 - 2 + 2 = 26
As a to the power of 2 is the same as a squared then how about this a2
An electron configuration refers to the distribution of electrons in orbitals. Since there are no ions given for this question, an electron configuration cannot be provided.
22/2 - 2
The 2s sublevel can hold a maximum of 2 electrons.
Not sure about five, but you can make 42 with 6 2s with this method: 2[(22)! - (2/2) - 2] = 42
A = (s, 2s), B = (3s, 8s) The midpoint of AB is C = [(s + 3s)/2, (2s + 8s)/2] = [4s/2, 10s/2] = (2s, 5s) Gradient of AB = (8s - 2s)/(3s - s) = 6s/2s = 3 Gradient of perpendicular to AB = -1/(slope AB) = -1/3 Now, line through C = (2s, 5s) with gradient -1/3 is y - 5s = -1/3*(x - 2s) = 1/3*(2s - x) or 3y - 15s = 2s - x or x + 3y = 17s