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Q: How do you write two binomials such that the product is equal to zero when x equals 3 or -5?

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The product of prime numbers for 336 is:2x2x2x2x3x7This is because all of that sum equals the total of 3362x2x2x3x7=336

It is simply 2.5 equals 2.500

2 x 2 x 3 x 7 = 84

If the product of three numbers is 140, then we can write 140 as aXbXc. Let a be 10 and let b be 2. Then 140 equals 10X2Xc, or 7 equals c. Thus, the remaining number is 7.

write the number 14as a product of prime factor?

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It means that the question has been written by someone who does not know what the word "polynomial" means, or else that this is a copy-and-paste by someone who knows even less! Only a trinomial can be written as a product of two binomials. No polynomial of any other order can!

The two binomials can be written as (x - a)(x + a), for any constant a. Proof: Expand using FOIL: (x - a)(x + a) = x2 + xa - xa - a2 Group: (x - a)(x + a) = x2 - a2 x2 - a2 is a difference of squares. Thus, the product of (x - a) and (x + a) is a difference of squares.

The sign that represents "is not equal to", is an equals sign with a line in it, such as â‰ . Therefore, you can write râ‰ 4.

As for example the product of -6 and 3 is equal to -18.

6x3=18

It is: 2 times 19 equals 38

45.5 is equal to 455% which also equals 455/100

52 times 1 equals 52 2 times 26 equals 52

It is impossible to write 90 as the product of two prime factors. 90 is equal to 2 x 32 x 5.

5 times 7 times 11 equals 385

The product of prime numbers for 336 is:2x2x2x2x3x7This is because all of that sum equals the total of 3362x2x2x3x7=336

That IS the equation. You may want to write with the equal sign: 6p = 24

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