Up to 999999, one short of a million.
For "millionths", adjust the zeroes so that there are six digits after the decimal point.
No. It terminates after six digits after the decimal point.
It's a repeating decimal equivalent to 0.285714... where the six digits will repeat.
There are 500000 such numbers.
As written, yes. If it keeps on going, no.
The probability of a specific sequence of six consecutive decimal digits occurring early in the decimal representation of pi is usually only about 0. 08% (or more precisely, about 0. 0762%). However, if the sequence can overlap itself (such as 123123 or 999999) then the probability is less. The Feynman point is the first occurrence of four and five consecutive identical digits, but not six.
1071428.571428 (the six decimal digits repeat indefinitely).
Seven, to start with, but the last of these digits is a zero. So effectively there will be six.
0.285714 where these six digits repeat indefinitely
The fraction 1/7 has the decimal value 0.142857142857142857..... The six digits 142857 keep repeating.
The number of significant figures in a number is equal to the number of digits to the left of the decimal point up to the first leading zero. It is then added to the number of total digits to the right of the decimal point. In this case, there are six significant digits.