Because it is divisible by numbers other than 1 and itself. 39 is divisible by 1, 3, 13, 39.
117 is not a prime number. It is divisible by 3. 3*39=117.
Because it is divisible by numbers other than 1 and itself.
Oh, dude, that's an easy one. So, what can go into 21 and 39? Well, technically, the numbers that can go into both 21 and 39 are 1 and 3. Like, it's not rocket science, but hey, math can be a little sneaky sometimes.
No, both are divisible by 13.
No, it is divisible by 1, 3, 13, 39.
Yes; if 39 is divided by 3, you get 13. Another way to check this is add 13+ 13+ 13, and you will get 39.
composite 3 goes into 3 or 30 3 goes into 9 so 3 goes into 39 13 + 13 + 13 = 39 = 3 x 13 ------------------------------------- Applying a divisibility test: To be divisible by 3, sum the digits of the number and if this sum is divisible by 3, then the original number is divisible by 3. As the test can be repeated on the sum, repeat the summing until a single digit remains; only if this number is one of {3, 6, 9} is the original number divisible by 3. For 39 this gives: 39 → 3 + 9 = 12 12 → 1 + 2 = 3 3 is one of {3, 6,9} so 39 is divisible by 3. As 39 is divisible by 3 (that is 3 is a factor of 39 that is less than 39) and 3 is greater than 1 then 39 is a composite number.
Because it is divisible by numbers other than 1 and itself. 39 is divisible by 1, 3, 13, 39.
If you are wanting factors there is: 1, 3, 13, 39
117 / 3 = 39 39 / 3 = 13 Giving us prime factors of 3, 3 and 13. Meaning it's divisible by: 3 3 * 3 = 9 3 * 13 = 39 13 So 117 is divisible by 3, 9, 13, and 39
39 is not divisible by 2, since it is odd. Looking at the next highest prime number 3, we see that it is divisible, so we divide by three until it is no longer divisible by 3: 39/3 = 13 13 is also prime, thus 3*13 is the prime factorization.
Yes it is - 39 times
3, 9, 13, and 39.
39 is divisible by 3. It equals 13. You can tell if a number is divisible by 3 by adding up the digits in the number and see if it is divisible by three. Here's and example: 197 1+9+7= 17 and 17 isn't divisible by three. 576 5+7+6= 18 and 3 goes into 18 6 times so it is divisible by 3
2, 3, 6, and 39
741 is divisible by 1, 3, 13, 19, 39, 57, 247, 741