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Why is 39 a composite number?
Because it is divisible by numbers other than 1 and itself. 39 is divisible by 1, 3, 13, 39.
Is 117 prime?
117 is not a prime number. It is divisible by 3. 3*39=117.
Why is 39 is not a prime number?
Because it is divisible by numbers other than 1 and itself.
Are 26 and 39 relatively prime?
No, both are divisible by 13.
How can you tell that 42 is divisible by 3?
To determine if 42 is divisible by 3, you can add up the digits of 42 (4 + 2 = 6) and check if the sum is divisible by 3. Since 6 is divisible by 3, then 42 is also divisible by 3. This is based on the rule that a number is divisible by 3 if the sum of its digits is divisible by 3.
Is 39 divisible by 2?
No, it is divisible by 1, 3, 13, 39.
Is 39 divisible by 3?
Yes; if 39 is divided by 3, you get 13. Another way to check this is add 13+ 13+ 13, and you will get 39.
Is 39 a prime or composite Explain how you know?
composite 3 goes into 3 or 30 3 goes into 9 so 3 goes into 39 13 + 13 + 13 = 39 = 3 x 13 ------------------------------------- Applying a divisibility test: To be divisible by 3, sum the digits of the number and if this sum is divisible by 3, then the original number is divisible by 3. As the test can be repeated on the sum, repeat the summing until a single digit remains; only if this number is one of {3, 6, 9} is the original number divisible by 3. For 39 this gives: 39 → 3 + 9 = 12 12 → 1 + 2 = 3 3 is one of {3, 6,9} so 39 is divisible by 3. As 39 is divisible by 3 (that is 3 is a factor of 39 that is less than 39) and 3 is greater than 1 then 39 is a composite number.
Why is 39 a composite number?
Because it is divisible by numbers other than 1 and itself. 39 is divisible by 1, 3, 13, 39.
39 divisible by?
If you are wanting factors there is: 1, 3, 13, 39
What are the positive factors of 117?
117 / 3 = 39 39 / 3 = 13 Giving us prime factors of 3, 3 and 13. Meaning it's divisible by: 3 3 * 3 = 9 3 * 13 = 39 13 So 117 is divisible by 3, 9, 13, and 39
What is the prime factor of 39 using exponential notation?
39 is not divisible by 2, since it is odd. Looking at the next highest prime number 3, we see that it is divisible, so we divide by three until it is no longer divisible by 3: 39/3 = 13 13 is also prime, thus 3*13 is the prime factorization.
Is 117 divisible by 3?
Yes it is - 39 times
What is 117 divisible by?
3, 9, 13, and 39.
Is 39 divisible by3?
39 is divisible by 3. It equals 13. You can tell if a number is divisible by 3 by adding up the digits in the number and see if it is divisible by three. Here's and example: 197 1+9+7= 17 and 17 isn't divisible by three. 576 5+7+6= 18 and 3 goes into 18 6 times so it is divisible by 3
What is 78 divisible by?
2, 3, 6, and 39
What are the divisible of 741?
741 is divisible by 1, 3, 13, 19, 39, 57, 247, 741
