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How many liters of a 40 percent acid solution must be added to 100 liters of a 25 percent solution to obtain a 30 percent solution?
Suppose L litres are required.
@ 40% it will contain 0.4L of the active ingredient.
Then total volume of mixture = L + 100 litres
and volume of active ingredient = 0.4L + 25 litres
The strength is (0.4L + 25)/(L + 100) = 30% = 0.3
(0.4L + 25) = 0.3*(L + 100)
0.4L + 25 = 0.3*L + 30
0.1L = 5
L = 50 litres.
What else can I help you with?
What is 10 percent added to 4.86?
10 percent added to 4.86 is 5.346.
What is 4 percent added to 900 dollars?
4% added to $900 = $936
What is 20 percent added to 250.00?
300.00
Convert 60 percent solution to 8 percent?
Answer: Take whatever volume of 60 percent solution you have, multiply that volume by 52 and then divide that amount by 8, this is how much water to add to get an 8% solution. ( or multiply by 13 and divide it in half, this is the same thing) Answer explained below. Think of 3 jars. The first has 60% solution, the next has just water, the third has 8% solution. So we want to know how much water to add. Now we need some equations. 60% solution is 60 units of something, and say we have a volume V of it. So the amount stuff in V is .6V. Just to clarify, the total volume of 60% liquid is V and let's say it is salt water. Then we have 60% of it is salt and the actual amount of salt we have is .6v. Now we are adding to the volume, but not adding salt. We add x liters to V so our total volume we add to get 8% is V+x. Now the 8% has (we use salt just to make this more concrete, but obviously cement would do the same or acid..bla bla bla) So the quantity of salt in our final solutin is .08(V+x), however, we only added water, so the amount of salt is the same. That means .6V=.08(V+x) so this is our equation! multiply by 100 to get rid of the decimals. We have 60V=8V+8x or 52V=8x so x=52V/8 That means for any given volume of water, we multiply the volume by 52 and divide by 8 to see how much water to add. Let's try it! Say V=8 Liters. I pick that since it should make the 8's cancel. So we have 8 liters of 60% salt solution. This mean we have .6(8) grams of salt, or 4.8 grams. Now we add 52 x/8 or 52 liters of water. Our total volume now is 52+8=60 liters and we did not add salt so we still have 4.8 grams. What percent solution is this? 4.8 grams/60 is .08% as desired so it works!
How much water is added to 32 percent UAN to make 28 percent UAN?
12.5%
How many liters of a 20 percent solution of acid should be added to 10 liters of a 30 percent solution of acid to obtain a 25 percent solution?
10 liters.
How much water must be added to 12 L of a 40 percent solution of alcohol to obtain a 30 percent solution?
4 litres
How many grams of sugar must be added to 60 grams of a solution that is 32 percent sugar to obtain a solution that is 50 percent sugar?
40.8 grams
How many gallons of 3 percent salt solution must be mixed with 50 gallons of 7 percent salt solution to obtain a 5 percent salt solution?
50 gallons @ 3% must be added.
How many qt of pure antifreeze must be added to 3 qt of a 10 percent antifreeze solution obtain a 20 percent antifreeze solution?
0.6 of a pint.
How much of an 18 percent solution of sulfuric acid should be added to 360 ml of a 10 percent solution to obtain a 15 percent solution?
To determine the amount of 18% solution to add: Let x = volume of 18% solution to be added. 0.18x + 0.10(360) = 0.15(x + 360) Solving for x, you would need to add 75 ml of the 18% solution to the 360 ml of 10% solution to obtain a 15% solution.
How many liters of water must be added to 7 liters of a 20 percent acid solution to obtain a 10 percent acid solution?
7 liters of a 20% acid solution consists of 1.4 liters of acid (20% of the total volume) mixed with 5.6 liters of water (80% of the total volume). The amount of acid isn't going to change in the new solution. You are just going to add enough water to make it a 10% solution instead of a 20% solution. So it will be more dilute. That means that 1.4 liters of acid will represent 1/10 of the volume of the new solution. So the total volume of the new solution will be 10 x 1.4 or 14 liters. The amount of water in the new solution will be 14 - 1.4 = 12.6 liters. That is a difference of 12.6 - 5.6 = 7 liters from the amount of water you started with. So you need to add 7 liters of water to the original 20% solution to make it a 10% solution. This makes sense because if you double the amount of the mixture from 7 liters to 14 liters and the amount of acid is unchanged, the solution will be half as strong.
How many quartz of pure antifreeze must be added to 6 quartz of a 10 percent antifreezesolution to obtain a 20 percent antifreeze solution?
4.2 quarts
How many liters of a 20 percent alcohol must be mixed with 40 liters of a 90 percent solution to get a 60 percent solution?
Let L be the liters to be added. Then (L) x (0.2) + (40 x 0.9) = (L + 40) x 0.6 0.2L + 36 = 0.6L + 24 36 - 24 = (0.6 - 0.2)L 12 = 0.4L L = 12/0.4 = 120/4 = 30 Liters
How much water should be added to 1 gallon of pure antifreeze to obtain a solution that is 60 percent antifreeze?
2 gallons.
How many kg of pure salt must be added to 8 kg of a 30 percent solution to obtain a 35 percent soltution Round to the nearest tenth?
0.6
How much water should be added to 15 g of salt solution to obtain 15 percent salt solution?
Dissolve 15 g salt in 100 mL water.
