Oh, dude, you're talking about four-digit numbers where every digit is even, right? So, we've got 2, 4, 6, and 8 to play with. Each place can have any of those four options, so it's like 4 choices for each of the 4 digits. That's 4x4x4x4, which is 256 numbers between 1000 and 9999 where all the digits are even.
From 1000 to 9999 (inclusive) there are 9999 - 1000 + 1 = 9000 integers. Half of which are even, half of which are odd. So the answer is 9000/2 = 4,500.
9*9*8*7 = 4536
Well, honey, the even integers between 1000 and 9999 can be found by dividing the total range by 2, since every other number is even. So, 9999 - 1000 = 8999, and 8999 divided by 2 gives you 4499 even integers. But remember, I'm not your calculator, so don't come crying to me if you can't count 'em all yourself!
Prime No: between 1000 to 9999= 54_( 42x3)
-9999. Or, if only positive numbers are being considered, then, 1000.
There are 2828 integers between 1000 and 9999.
90 palindromes.
From 1000 to 9999 (inclusive) there are 9999 - 1000 + 1 = 9000 integers. Half of which are even, half of which are odd. So the answer is 9000/2 = 4,500.
There are 3168 such numbers.
There are 120 of them.
There are 1,000 positive integers between 1,000 and 9,999, inclusive, that are divisible by nine.
9*9*8*7 = 4536
from 1000 to 9999, ie 9999 - 999 = 9000
Well, honey, the even integers between 1000 and 9999 can be found by dividing the total range by 2, since every other number is even. So, 9999 - 1000 = 8999, and 8999 divided by 2 gives you 4499 even integers. But remember, I'm not your calculator, so don't come crying to me if you can't count 'em all yourself!
952 of them.
An infinite amount
Prime No: between 1000 to 9999= 54_( 42x3)