Yes, if the discriminant is zero, then there will be a double root, which will be real.
Also, If the discriminant is positive, there will be two distinct real solutions. But if the discriminant is negative, then you will have two complex solutions.
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ax2+bx+c=0 with a,b and c real discriminant D=b2-4ac if D >0 then there are 2 real zeros if D = 0 then there is one real zero if D<0 then there are two imaginary zeros There are no other possibility for D For further information search for fundamental theorem of algebra
No because the discriminant is less than zero.
True. Complex numbers have a real part and an imaginary part. If either one of these is zero, the complex number will be a pure real or a pure imaginary.
A non complex number is a number that does not have any imaginary component. An imaginary component is a non zero factor of the square root of -1, in other words, the imaginary number i.
x^2 + 4x + 5 cannot be factored because its discriminant is less than zero.