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What else can I help you with?
What kind of solution would have a ka value that is much less than one?
A Weakly Acidic Solution
What kind of solution would have a Kb value that is much greater than 1?
A strongly basic solution
What kind of number is -3.5?
a negative rational number
Can you help me with this simultaneous equation 2x y4 y2x²-x 3?
No because it's not a simultaneous equation but some kind of algebraic expression
Square root of -1.375?
If you want a real number as an answer, then there is no solution - no real number squared will give you a negative result. If complex numbers are acceptable, just take the square root of the positive number, and add an "i" at the end. For example, the square root of (-4) is 2i. Whether or not a complex number is acceptable depends on the kind of problem. The same happens for negative and fractional numbers; for some problems, a negative number is acceptable as an answer, for others not.
How do you use the discriminant to find the number and type of zeros of a function?
If the discriminant is positive, then the function has two real zeros. If it is zero, then the function has one real zero. If it is negative, then it has two complex conjugate zeros.This assumes that we are talking about a standard second order polynomial equation, i.e. quadratic equation, in the form Ax2 + Bx + C = 0, and that the discriminant is B2 - 4AC, which is a part of the standard solution of these kind of equations.
What multiples to 360 and adds to 37?
397
Is 0 the same as an equation with no solution?
I understand why you ask...but the answer is no.As a mathematical object, zero is an integer -- a number. As such, zero could easily be a SOLUTION to an EQUATION. But it's not the same as an equation. An equation is a different kind of mathematical object entirely.It's probably a good idea to try looking at zero not as "nothing", but as something: the middle point between positive and negative numbers.
An equation has one solution?
A linear equation in one variable has one solution. An equation of another kind may have none, one, or more - including infinitely many - solutions.
What the solution to this system of equation y-3x-2 6x2y-4?
There is none because its not an equation but some kind of algebraic expression.
What kind of solution is H2O?
H2O is the chemical equation (not solution) for water. It means: 2 atoms of hydrogen, and 1 atom of oxygen.
How do you know when an equation has no solution?
when you're really good in that kind of equation, but cannot, no matter what u do, CANNOT figure it out! when you look it up and can't find the answer in the back of the book. It depends on what kind of problem it is.
What kind of solute particles are present in a solution of an ionic compound?
The individual particles of an ionic crystal are positive and negative ions.
What kind of compounds produce ions in solution?
Salts produce (metallic) positive catIONS and negative anIONS (of non-metals)
What kind of quantities can be added or subtracted from both sides of an equation?
You can add or subtract any quantity on both sides of an equation, without changing the equation's solution set. Just make sure you add or subtract the same thing on both sides.
What kind of equation is 5x plus 15 - 7x?
No kind: it is an expression, not an equation.
What is the answer for x x -6x-8 equals -56?
x² - 6x -8 = -56 <=> x² -6x + 48 = 0 We now calculate the discriminant (which equals b²-4ac for an equation of the form ax² + bx + c-: D = b²-4ac = (-6)² - 4*1*48 = 36 - 192 = -156 I don't know what kind of course in calculus you are taking, but if you only want the real answers to this equation, you can stop here because the discriminant is negative, meaning there are no real solutions. However, there are complex solutions to this equation The complex roots of D are sqrt(156)*i=12,5*i and -sqrt(156)*i=-12,5*i There are two solutions to a quadratic equation, namely: x1 = (-b + sqrt(D))/(2*a) and x2 = (-b - sqrt(D))/(2*a) so the two solutions we find for this equation are: x1 = (-b + sqrt(D))/(2*a) = (6+12,5i)/2 = 3+6,25i and x2 = (-b - sqrt(D))/(2*a) = (6-12,5i)/2 = 3-6,25i x1 and x2 are complex solutions to this quadratic equation.
