To determine if 42 is divisible by 3, you can add up the digits of 42 (4 + 2 = 6) and check if the sum is divisible by 3. Since 6 is divisible by 3, then 42 is also divisible by 3. This is based on the rule that a number is divisible by 3 if the sum of its digits is divisible by 3.
741 is an odd number so is not divisible by 2 741/3 = 247 so yes divisible by 3
1262 is even, so 1262 is divisible by 2. 1 + 2 + 6 + 2 = 11 which is not divisible by 3 nor 9, so 1262 is not divisible by 3 nor 9.
Answer - How do you tell if a number is divisible by 3?you add all the digits in the number and see if that number can be divided by 3 Answer - A whole number is divisible by 3 if the sum of its digits is divisible by what?Three (3) Examples:* 27 -- 2+7=9 * 13452 -- 1+3+4+5+2=15 -- 1+5=6If the sum of the digits is divisible by 3, the number is also divisible by 3. Or just do the division.
3 yes, 2 no.
1, 2, 571, 1142.
1, 2, 571, 1142
123 is not divisible by 2 it is divisible by 3
416 is divisible by 2 but is not divisible by 3.
Yes, it is divisible by 2 because it ends with 2, it is also divisible bye 3 because 1+3+2=6. 6 is divisible by 3, therefor 132 is divisible by 3.
NO!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! 2 is divisible by 3
yep it is because 2 is divisible by 2 and 3 is divisible by 3 and 0 is divisible by 5 have fun suckers!
2+3+2+6=13 which is not divisible by 3 thus 2326 is not divisible by 3
To be divisible by 6, the number must be divisible by both 2 and 3:To be divisible by 2 the last digit must be even, ie one of {0, 2, 4, 6, 8};To be divisible by 3, sum the digits of the number and if this sum is divisible by 3, then the original number is divisible by 3.As the test can be repeated on the sum, repeat the summing until a single digit remains; only if this number is one of {3, 6, 9} is the original number divisible by 3.If the number is not divisible by 2 or 3 (or both) then the number is not divisible by 6.examples:126Last digit is even so it is divisible by 2 1 + 2 + 6 = 9 which is divisible by 3, so it is divisible by 3→ 126 is divisible by both 2 and 3, so it is divisible by 6124Last digit is even so it is divisible by 2 1 + 2 + 4 = 7 which is not divisible by 3, so it is not divisible by 3→ 126 is divisible by 2 but not divisible by 3, so it is not divisible by 6123Last digit is not even so it is not divisible by 2 We can stop at this point as regardless of whether it is divisible by 3 or not, it will not be divisible by 6. However, for completeness:1 + 2 + 3 = 6 which is divisible by 3, so it is divisible by 3→ 123 is divisible by 3 but not divisible by 2, so it is not divisible by 6121Last digit is not even so it is not divisible by 2 We can stop at this point as regardless of whether it is divisible by 3 or not, it will not be divisible by 6. However, for completeness:1 + 2 + 1 = 4 which is not divisible by 3, so it is not divisible by 3→ 121 is not divisible by either 2 or 3, so it is not divisible by 6
1x6,743 not divisible by 2 no its not divisible by 3????
6 and its multiples are divisible by 2 and 3.
2 is NOT divisible by 3.