1262 is even, so 1262 is divisible by 2.
1 + 2 + 6 + 2 = 11 which is not divisible by 3 nor 9, so 1262 is not divisible by 3 nor 9.
It is divisible by 2, 3, 4, 6 and 9.
For each given number, add the digits. If the sum comes to nine, then it is divisible by '9'. 234 ; 2 + 3 + 4 = 9 So is dividble by '9' 345 ; 3 + 4 + 5 = 12 = 1 + 2 = 3 Not divisible by '9' 567 ; 5 + 6 + 7 = 18 = 1 + 8 = 9 so is divisible by '9'.
No. 189 is only evenly divisible by 3 and 9 (from the set provided). Using the following rules of divisibility on the number 189: Divisible by 2? No - the number is not even Divisible by 3? Yes - the sum of the digits (1 + 8 + 9 = 18) is divisible by 3 Divisible by 4? No - the last two digits are not evenly divisible by 4 Divisible by 5? No - the last digit is not a 0 or a 5 Divisible by 6? No - the number is not even Divisible by 9? Yes - the sum of the digits is divisible by 9 Divisible by 10? No - the number is not divisible by 2 or 5
as 9 is made of 3 times 3 so any number (such as 90) which is divisible by 9 will also be divisible by 3 and the answer will be 3 times bigger so 90/9 is 10 then 90/3 = 30 which is 10 x 3 Example: same for any number that is divisible by 14 will also be divisible by 7 (or also 2) as 14 = 7 x 2 or divisible by say 50 is also divisible by 5 or 10 as 50 = 5 x 10 and so on ...
2, 5, and 10 . . . Yes. 3 and 9 . . . . . . No.
Using the tests for divisibility:Divisible by 3:Add the digits and if the sum is divisible by 3, so is the original number: 2 + 3 + 4 = 9 which is divisible by 3, so 234 is divisible by 3Divisible by 6:Number is divisible by 2 and 3: Divisible by 2:If the number is even (last digit divisible by 2), then the whole number is divisible by 2. 234 is even so 234 is divisible by 2.Divisible by 3:Already shown above to be divisible by 3. 234 is divisible by both 2 & 3 so 234 is divisible by 6Divisible by 9:Add the digits and if the sum is divisible by 9, so is the original number: 2 + 3 + 4 = 9 which is divisible by 9, so 234 is divisible by 9Thus 234 is divisible by all 3, 6 & 9.
The numbers 2, 3, and 9 are all divisible by 1.
Last digit (0) is even, so it is divisible by 2 4 + 3 + 2 + 0 = 9 which is divisible by 3, so it is divisible by 3 last digit is 0 or 5, so it is divisible by 5 4 + 3 + 2 + 0 = 9 which is divisible by 9, so it is divisible by 9 last digit is 0, so it is divisible by 10 → 4320 is divisible by all the numbers 2, 3, 5, 9, 10
Yes, 234 is divisible by 2, 3, and 9. It is even, which means it is divisible by 2. The sum of its digits (2 + 3 + 4 = 9) is divisible by 3, confirming that 234 is also divisible by 3 and 9. However, 234 is not divisible by 5 or 10, as it does not end in 0 or 5.
42 is divisible by 2, 3 and 6 but not by 9.
It is evenly divisible by 2 and 10 but not by 3 and 9.
no because to be divisible by 9 the number has to equal 9 for instance 2+9+3+8=22 so it is not divisible by 9. But 32121 3+2+1+2+1=9 so it is divisible by 9
Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.
20 is divisible by 2, 5 and 10. It is not exactly divisible by 3 or 9.
Yes, 599422 is divisible by 3. The sum of its digits is 5+9+9+4+2+2 = 31, which is divisible by 3.
It is divisible by 2, 5 and 10, but not 3 and 9.
yes. 2 + 1 + 6 = 9 9 is divisible by 3 so 216 is divisible by 3.