To find a number between 120 and 130 that is divisible by 3 and has a digit sum divisible by 4, we first consider the numbers in that range: 121, 122, 123, 124, 125, 126, 127, 128, 129. Next, we calculate the digit sum of each number: 121 (1+2+1=4), 122 (1+2+2=5), 123 (1+2+3=6), 124 (1+2+4=7), 125 (1+2+5=8), 126 (1+2+6=9), 127 (1+2+7=10), 128 (1+2+8=11), 129 (1+2+9=12). Therefore, the number between 120 and 130 that is divisible by 3 and has a digit sum divisible by 4 is 123.
You could be 121.
No, 60 is.
Oh, what a happy little question! To find a number divisible by 2, 3, 5, 6, and 10, we need to look for the least common multiple of these numbers. The smallest 3-digit number that fits the bill is 120. Just like painting a beautiful landscape, finding the right number takes patience and a gentle touch.
Yes, 120 is divisible by 3. A good rule of thumb for the multiples of 3 is to add up the digits in the number. If the number that comes out is divisible by 3, then it is a multiple of 3. For example, in 120, 1 + 2 + 0 = 3. Therefore, the number is divisible by 3. The process can be repeated for larger numbers. For example, 2688 is divisible by 3 because 2 + 6 + 8 + 8 = 24, and 2 + 4 = 6.
The only prime number between 120 and 130 is 127.
120
How about: 108
120 your welcome
120
120, 150, 180
How about: 120
A three-digit number that is divisible by both three and four must also be divisible by their least common multiple, which is twelve. The smallest three-digit number divisible by twelve is 108, and the largest is 996. Therefore, any three-digit number that is a multiple of twelve, such as 120, 144, or 480, will meet the criteria of being divisible by both three and four.
120
Any 3 digit number that ends with a "0." 100, 110, 120 and 130.
There are many. Some are: 100, 104, 108, 112, 116, 120.
105 120 135 150 165 180 195 210 225 240 255 270 285 300... Any 3-digit number divisible by 15.
There is no such number. Once you have one n-digit number which is divisible by 4 then 10 times that number will be an n+1 digit number which is divisible by 4. And this process can continue ad infinitum.