To find a number between 120 and 130 that is divisible by 3 and has a digit sum divisible by 4, we first consider the numbers in that range: 121, 122, 123, 124, 125, 126, 127, 128, 129. Next, we calculate the digit sum of each number: 121 (1+2+1=4), 122 (1+2+2=5), 123 (1+2+3=6), 124 (1+2+4=7), 125 (1+2+5=8), 126 (1+2+6=9), 127 (1+2+7=10), 128 (1+2+8=11), 129 (1+2+9=12). Therefore, the number between 120 and 130 that is divisible by 3 and has a digit sum divisible by 4 is 123.
You could be 121.
No, 60 is.
Oh, what a happy little question! To find a number divisible by 2, 3, 5, 6, and 10, we need to look for the least common multiple of these numbers. The smallest 3-digit number that fits the bill is 120. Just like painting a beautiful landscape, finding the right number takes patience and a gentle touch.
Yes, 120 is divisible by 3. A good rule of thumb for the multiples of 3 is to add up the digits in the number. If the number that comes out is divisible by 3, then it is a multiple of 3. For example, in 120, 1 + 2 + 0 = 3. Therefore, the number is divisible by 3. The process can be repeated for larger numbers. For example, 2688 is divisible by 3 because 2 + 6 + 8 + 8 = 24, and 2 + 4 = 6.
The only prime number between 120 and 130 is 127.
120
How about: 108
120 your welcome
120, 150, 180
120
How about: 120
120
Any 3 digit number that ends with a "0." 100, 110, 120 and 130.
There are many. Some are: 100, 104, 108, 112, 116, 120.
105 120 135 150 165 180 195 210 225 240 255 270 285 300... Any 3-digit number divisible by 15.
There is no such number. Once you have one n-digit number which is divisible by 4 then 10 times that number will be an n+1 digit number which is divisible by 4. And this process can continue ad infinitum.
There are no numbers between 108 and 120 that have an even ten's digit. If you call 'zero' an even number, then ' 109 ' would qualify. But the whole exercise is still not too satisfying.