NO.
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1 and 19.
19 divisible by 5, 14 divisible by 7. Of these, 3 divisible by both.
1, 19, 29, 551
19,38,57,76, etc. The previous answer (deleted)was wrong, because 1 and 19 are factors of 19, not multiples.
No. it is composite. 57 is divisible by 3 and 19 :)