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No. 189 is only evenly divisible by 3 and 9 (from the set provided).
Using the following rules of divisibility on the number 189:
Divisible by 2? No - the number is not even
Divisible by 3? Yes - the sum of the digits (1 + 8 + 9 = 18) is divisible by 3
Divisible by 4? No - the last two digits are not evenly divisible by 4
Divisible by 5? No - the last digit is not a 0 or a 5
Divisible by 6? No - the number is not even
Divisible by 9? Yes - the sum of the digits is divisible by 9
Divisible by 10? No - the number is not divisible by 2 or 5
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3 <><><> 3 is only divisible by 1 and itself. whereas 4 and 10 are divisible by other numbers. 4 is divisible by 1,2,4. 10 is divisible by 1,2,5,10 <><><> A prime number is a number that is evenly divisible only by itself and one. Therefore, 3 is the prime number. 4 is divisible by 1, 2, and 4. 10 is divisible by 1, 2, 5, and 10. Three cannot be divided evenly by any other whole number. So, 3 is the prime number.
Why any number that is divisible by 9 is also divisible by 3?
as 9 is made of 3 times 3 so any number (such as 90) which is divisible by 9 will also be divisible by 3 and the answer will be 3 times bigger so 90/9 is 10 then 90/3 = 30 which is 10 x 3 Example: same for any number that is divisible by 14 will also be divisible by 7 (or also 2) as 14 = 7 x 2 or divisible by say 50 is also divisible by 5 or 10 as 50 = 5 x 10 and so on ...
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2, 5, and 10 . . . Yes. 3 and 9 . . . . . . No.
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