10 is divisible by 2 and 5 12 by 2, 3 , 4, and 6 18 by 2, 3, 6, and 9 24 by 2, 3, 4, 6, 8, and 12 27 by 3 and 9 Their prime factors would be 10: 2 * 5 12: 2 * 2 * 3 18: 2 * 3 * 3 23: 2 * 2 * 2 * 3 27: 3 * 3 * 3
It is divisible by 2, 3, 4, 6 and 9.
3 <><><> 3 is only divisible by 1 and itself. whereas 4 and 10 are divisible by other numbers. 4 is divisible by 1,2,4. 10 is divisible by 1,2,5,10 <><><> A prime number is a number that is evenly divisible only by itself and one. Therefore, 3 is the prime number. 4 is divisible by 1, 2, and 4. 10 is divisible by 1, 2, 5, and 10. Three cannot be divided evenly by any other whole number. So, 3 is the prime number.
as 9 is made of 3 times 3 so any number (such as 90) which is divisible by 9 will also be divisible by 3 and the answer will be 3 times bigger so 90/9 is 10 then 90/3 = 30 which is 10 x 3 Example: same for any number that is divisible by 14 will also be divisible by 7 (or also 2) as 14 = 7 x 2 or divisible by say 50 is also divisible by 5 or 10 as 50 = 5 x 10 and so on ...
2, 5, and 10 . . . Yes. 3 and 9 . . . . . . No.
It is divisible by 2 and 3. It isn't divisible by 5 and 10.
27 is divisible by three because the sum of 2 and 7 is divisible by three. However, this trick only works with the numbers 3 and 9. 27 divided by 3 is 9.
It is evenly divisible by 2 and 10 but not by 3 and 9.
Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.
9 is divisible by 3 10 is divisible by 2, 5 and 10. Everything else, no.
20 is divisible by 2, 5 and 10. It is not exactly divisible by 3 or 9.
For starters, the number 3 is divisible by 3 but not by 2. Next, 9, 27 etc. All the odd multiples of 3 are divisible by 3 but not 2. So there is an infinite number of numbers that are divisible by 3 and not 2.
It is divisible by 2, 5 and 10, but not 3 and 9.
54 is divisible by 2. Quotient is 27. 54 is divisible by 3. Quotient is 18. 54 is divisible by 9. Quotient is 6.
How about 27
10 is divisible by 2 and 5 12 by 2, 3 , 4, and 6 18 by 2, 3, 6, and 9 24 by 2, 3, 4, 6, 8, and 12 27 by 3 and 9 Their prime factors would be 10: 2 * 5 12: 2 * 2 * 3 18: 2 * 3 * 3 23: 2 * 2 * 2 * 3 27: 3 * 3 * 3
It is divisible by 2 & 3. It is not divisible by 5, 9 & 10. 534 is even → divisible by 2 5 + 3 + 4 = 12 → divisible by 3 534 does not end in 0 or 5 → not divisible by 5 5 + 3 + 4 = 12 → not divisible by 9 534 does not end in 0 → not divisible by 10