If by "radical" you mean "square root of", then yes. Both square roots of 25 are real numbers.
No, it is not.
The number word for the number 6 is "six".
Yes well at least that is what is what ive learnt
Nearly any number you can think of is a Real Number. So 8 is a real number.
It can be.
No it is not.
Yes.
If by "radical" you mean "square root of", then yes. Both square roots of 25 are real numbers.
Six is a real number. If you mean "six ninths", yes, that's a real number. If you mean "one ninth", that's also a real number.
Odd
negative
Not necessarily. If it is the same radical number, then the signs cancel out. Radical 5 times radical 5 equals 5. But if they are different, then you multiply the numbers and leave them under the radical sign. Example: radical 5 * radical 6 = radical 30
I'm not quite sure, but when the number inside the radical (square root sign) is negative, there is a no real-number solution.
Such an equation has a total of six roots; the number of real roots must needs be even. Thus, depending on the specific equation, the number of real roots may be zero, two, four, or six.
A number under a radical sign is known as a radicand.
The number under the radical sign (also known as the radical) is called the radican.