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Sure. √6 , the square root of 6, is approximately 2.44949. It's an irrational number --you can't get it as the ratio of any two integers -- but it's real. See Can_a_real_number_be_an_irrational_number

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12y ago

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Related Questions

Is a radical a real number?

It can be.


Is radical 3 a real number?

No it is not.


Can you divide a radical by a real whole number?

Yes.


Is radical 25 a real number?

If by "radical" you mean "square root of", then yes. Both square roots of 25 are real numbers.


Is six and ninths are real numbers?

Six is a real number. If you mean "six ninths", yes, that's a real number. If you mean "one ninth", that's also a real number.


Any radical expression with a radicand and an even index is not a real number?

negative


Any radical expression with a negative radicand and a index is a real number?

Odd


When you multiply a radical number with another radical number do the radical signs cancel each other out?

Not necessarily. If it is the same radical number, then the signs cancel out. Radical 5 times radical 5 equals 5. But if they are different, then you multiply the numbers and leave them under the radical sign. Example: radical 5 * radical 6 = radical 30


What is the name of a square root of a negative number?

I'm not quite sure, but when the number inside the radical (square root sign) is negative, there is a no real-number solution.


What is the number under the radical?

A number under a radical sign is known as a radicand.


What is the number under the radical sign known as?

The number under the radical sign (also known as the radical) is called the radican.


How many real roots do we have if the polynomial equation is in degree six?

Such an equation has a total of six roots; the number of real roots must needs be even. Thus, depending on the specific equation, the number of real roots may be zero, two, four, or six.