"Most of the time" is somewhat problematic, since we are dealing with infinite sets of numbers. But it is tempting to say that. The fact is, any number can be a cube root, since you can cube any number by multiplying it by itself twice. But the cube root of a whole number is always either a whole number or an irrational number. And it is true that if N is any reasonably large whole number (say, 1000 or more), the majority (in fact, at least 99%) of the whole numbers from 1 to N have irrational cube roots.
Answer 1
No. Most of the time it's an irrational number.
any number that doesn't have a cube root eg (33) 27 is a cubic number cube root is 3
No, it may be not even a rational number. Square root of 2 is 1,414213562... for example.
Any odd root, for example the cube root, of -3.24 is a real number.
6859. Cube root of 9999 is 21.54, so find the largest prime number less than that (19), then cube that number. 19^3=6,859
1728 is even so it cannot have an odd cube root.
How about 27 whose cube root is 3 which is a rational whole number.
a perfect cube
a perfect cube
27 is a perfect cube.
No, it's not. The cube root of 16 is just under 2.52
That's a perfect cube.
The answer is: perfect cube
not a whole number. 6 is 216, and 7 is 343 the cube root of 333 is 6.93
It is always plus
No - rounded to two decimal places, the cube root of 880 is 9.58.
No - rounded to two decimal places, the cube root of 720 is equal to 8.96.
nope! take the square root of 5, 2.236067978... which is not a whole number! hope this helps!