"Most of the time" is somewhat problematic, since we are dealing with infinite sets of numbers. But it is tempting to say that. The fact is, any number can be a cube root, since you can cube any number by multiplying it by itself twice. But the cube root of a whole number is always either a whole number or an irrational number. And it is true that if N is any reasonably large whole number (say, 1000 or more), the majority (in fact, at least 99%) of the whole numbers from 1 to N have irrational cube roots.
Answer 1
No. Most of the time it's an irrational number.
any number that doesn't have a cube root eg (33) 27 is a cubic number cube root is 3
No, it may be not even a rational number. Square root of 2 is 1,414213562... for example.
Any odd root, for example the cube root, of -3.24 is a real number.
6859. Cube root of 9999 is 21.54, so find the largest prime number less than that (19), then cube that number. 19^3=6,859
1728 is even so it cannot have an odd cube root.
How about 27 whose cube root is 3 which is a rational whole number.
a perfect cube
a perfect cube
27 is a perfect cube.
No, it's not. The cube root of 16 is just under 2.52
That's a perfect cube.
The cube root of an odd number is always an odd number. This is because when you cube an odd number, the result remains odd. For example, the cube of 3 (which is odd) is 27 (also odd). Therefore, taking the cube root of an odd number will yield an odd result.
The answer is: perfect cube
not a whole number. 6 is 216, and 7 is 343 the cube root of 333 is 6.93
It is always plus
No - rounded to two decimal places, the cube root of 880 is 9.58.
No - rounded to two decimal places, the cube root of 720 is equal to 8.96.