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No, it's not. The cube root of 16 is just under 2.52

Q: Is the cube root of 16 a whole number?

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The cube root of 16, which is 2.52 approx.The cube root of 16, which is 2.52 approx.The cube root of 16, which is 2.52 approx.The cube root of 16, which is 2.52 approx.

cube root of 64 = 4 4 x 4 = 16, and 16 x 4 = 64 4 cube = 64

square it and cube it

Yes because it is 4

The square root of 16 is 4. Four cubed (43) is 64.

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The square root of 16 is 4 which is a whole number.

No.

The cube root of 16, which is 2.52 approx.The cube root of 16, which is 2.52 approx.The cube root of 16, which is 2.52 approx.The cube root of 16, which is 2.52 approx.

cube root of 64 = 4 4 x 4 = 16, and 16 x 4 = 64 4 cube = 64

4^2 = 16 ; Difference is '5' Not the cube root 5^2 = 25 ; Difference is '3' Not the cube root 6^2 = 36 ; Difference is '3' Not the cube root 7^2 = 49 ; Difference is '5' Not the cube root 8^2 = 64 ; Difference is ''2' '2' is the cube root of '8' 9^2 = 81 ; Difference is 7 . Not the cube root 10^2 = 100 ; Difference is '1' Not the cube root. Hence the number is '8' . The cube root of '8' is '2' ( 2 x 2 x 2 = 8 )

Yes, because the square root of 16 is 4 and as a whole number it is an integer

square it and cube it

2.5198421

16

Yes because it is 4

How about 16 as one example

64