1728 is even so it cannot have an odd cube root.
The cube number pattern doesn't end.The first 12 cube numbers are:1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, 1331, 1728...
and the question is ... ?
Any odd root, for example the cube root, of -3.24 is a real number.
If I understand the question correctly, you want the probability of each cube showing an odd number. If the number cubes are fair, then the answer is 1/4.
27 is an odd number.
the cube root of 1728 is 12
To find the number that, when multiplied by itself three times, equals 1728, you need to calculate the cube root of 1728. The cube root of 1728 is 12, since 12 × 12 × 12 = 1728. Therefore, the number is 12.
The cube root of an odd number is always an odd number. This is because when you cube an odd number, the result remains odd. For example, the cube of 3 (which is odd) is 27 (also odd). Therefore, taking the cube root of an odd number will yield an odd result.
To find the number that, when multiplied by itself three times, equals 1728, we need to calculate the cube root of 1728. The cube root of 1728 is 12, since (12 \times 12 \times 12 = 1728). Thus, the number you are looking for is 12.
There are five odd numbers on an odd number cube?
The cube root of 1728 is: 121728 cubed is: 5,159,780,352
the cube of 1 is 1 as is any operation done against 1 3x3x3= 27 so 27 is the cube of the odd number 3
Because 123 = 1728
12
Half of them.
There are 6 numbers total; odd numbers are 1, 3, 5; then a 6 is added so the probability of rolling an odd number or a 6 on a number cube is 4/6 or 2/3 or 66.67%.
A standard number cube has numbers 1-6, so there's a 50% (or one-half) chance of rolling both an odd or even number.