1728 is even so it cannot have an odd cube root.
and the question is ... ?
The cube number pattern doesn't end.The first 12 cube numbers are:1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, 1331, 1728...
Any odd root, for example the cube root, of -3.24 is a real number.
27 is an odd number.
If I understand the question correctly, you want the probability of each cube showing an odd number. If the number cubes are fair, then the answer is 1/4.
the cube root of 1728 is 12
To find the number that, when multiplied by itself three times, equals 1728, you need to calculate the cube root of 1728. The cube root of 1728 is 12, since 12 × 12 × 12 = 1728. Therefore, the number is 12.
There are five odd numbers on an odd number cube?
The cube root of 1728 is: 121728 cubed is: 5,159,780,352
the cube of 1 is 1 as is any operation done against 1 3x3x3= 27 so 27 is the cube of the odd number 3
Because 123 = 1728
12
Half of them.
There are 6 numbers total; odd numbers are 1, 3, 5; then a 6 is added so the probability of rolling an odd number or a 6 on a number cube is 4/6 or 2/3 or 66.67%.
A standard number cube has numbers 1-6, so there's a 50% (or one-half) chance of rolling both an odd or even number.
purple
and the question is ... ?