LL
Molar mass is a whole number multiple of the Empirical formula mass
Molar Mass of Al: 2(27.0g/mol) = 54.0g/mol Molar Mass of O: 3(16.0g/mol) = 48.0g/mol Molar Mass of compound: 102.0g.mol (54.0g/mol / 102.0g/mol) x 100% = 52.9%
· Assume that you have 100.0 g sample of the compound · Calculate the amount of each element in the sample · Convert the mass composition of each element to a composition in moles by dividing by the appropriate molar mass
18g/mol
First of all, it's CuSO4*5H2O (notice the capital "O" in the first part of the formula). The compound is called copper(II) sulfate pentahydrate, and if we wish to find the percent by mass of water, we need to find the molar mass of the hydrate first. Cu = 63.55 g/molS = 32.07 g/molO x 4 = 16.00 g/mol x 4 = 64.00 g/molH2O x 5 = 18.02 g/mol x 5 = 90.10 g/molNow add them all together and you get a molar mass of 249.72 g/molOf that 249.72 grams, 90.10 grams is water, so to find the percentage by mass that is water, simply divide 90.10 g by 249.72 g and multiply the result by 100%:90.10 g / 249.72 g x 100% = 36.08% water
molar mass of unknown/molar mass of empirial = # of empirical units in the molecular formula. Example: empirical formula is CH2O with a molar mass of 30. If the molar mass of the unknown is 180, then 180/30 = 6 and molecular formula will be C6H12O6
In order to find molecular formula from empirical formula, one needs to know the molar mass of the molecular formula. Then you simply divide the molar mass of the molecular formula by the molar mass of the empirical formula to find out how many empirical formulae are in the molecular formula. Then you multiply the subscripts in the empirical formula by that number.
Empirical formula = C3H5O Molar mass of empirical formula = 3(12.01)+5(1.008)+1(16) = 57.07 Molar mass of molecular fomula = 114.15 n = Molar mass of molecular fomula/Molar mass of empirical formula = 114.15/57.07 n = 2 Molecular formula = n(empirical formula) Molecular formula = 2(C3H5O) = C6H10O2 Check: 6(12.01)+10(1.008)+2(16)= 114.14
Cs2O2
N10H20Cl10
The molecular formula of a compound can not be determined solely based on its molar mass. In this case, without additional information, it is not possible to determine the molecular formula of the compound CH2.
the empirical formula and the molar mass
Firstly divide percentages by molar mass of that elementC65.45/12.01=5.45H5.45/1.01=5.40O29.09/16=1.82Then divide the result of the first step by the smallest answerC5.45/1.82=3H5.40/1.82=3O1.82/1.82=1Empirical Formula is C3H3OIf the molar mass is 110.1 we can divide this by our empirical formulas molar mass to get the molecular formula.so 110.1/(12.01x3+1.01x3+16)=110.1/55.06=2so the molecular formula is C6H6O2
C7h6o2
C26h38o4
molar mass over grams of elementThe above answer is somewhat correct. In order to find the molecular formula when given the empirical formula, you must first find the molar mass of the empirical formula.MOLAR MASS# atoms element A x Atomic Mass element A (Periodic Table) = mass A# atoms element B x atomic mass element B (periodic table) = mass B... etc.Add up all of the mass values found above and you have the molar mass.Then, after you have found the empirical formula's molar mass, you divide the molar mass of the molecular formula by the empirical formula's molar mass (solving for n).MOLECULAR FORMULA EQUATION: N (Empirical formula) (read as N times empirical formula) where:N = Molar mass substance---- Molar Mass emp. form.
molar mass over grams of elementThe above answer is somewhat correct. In order to find the molecular formula when given the empirical formula, you must first find the molar mass of the empirical formula.MOLAR MASS# atoms element A x Atomic Mass element A (Periodic Table) = mass A# atoms element B x atomic mass element B (periodic table) = mass B... etc.Add up all of the mass values found above and you have the molar mass.Then, after you have found the empirical formula's molar mass, you divide the molar mass of the molecular formula by the empirical formula's molar mass (solving for n).MOLECULAR FORMULA EQUATION: N (Empirical formula) (read as N times empirical formula) where:N = Molar mass substance---- Molar Mass emp. form.