4
They don't really have a start; they extend indefinitely in both directions.
It is 10 crossovers.
To convert a 1x4 demultiplexer (demux) to a 1x8 demux, you can cascade two 1x4 demuxes. Connect the output of the first 1x4 demux, which will have four outputs, to the select lines of a second 1x4 demux. The first demux's select lines determine which of its four outputs is active, while the second demux further divides that selected output into eight, effectively achieving the desired 1x8 demux functionality.
A numberline is never-ending. It goes to infinity to the right and to negative infinity to the left... Not always it depends on what nimber line it is.
Think of the numbers on the number line as years, months, or dates of the month. You could explain the event in a text box close to the corresponding date, then draw an arrow from the box to the location of the date on the number line.
An N-2N decoder is a digital circuit that converts N input lines into 2^N output lines. For each unique combination of the input lines, one specific output line is activated while all others remain inactive. For instance, if there are 3 input lines (N=3), the decoder will produce 2^3 = 8 output lines, allowing it to represent all combinations of the 3 inputs. This type of decoder is commonly used in memory address decoding and data routing applications.
An n-to-2^n decoder has n input lines. Each combination of the n input lines corresponds to one of the 2^n output lines being activated. Thus, for a decoder to function correctly, it requires exactly n input lines to decode the binary input into a specific output line.
A 64-output line decoder has 6 data inputs. This is because a decoder's number of outputs (N) is related to the number of inputs (n) by the formula ( N = 2^n ). Therefore, to achieve 64 outputs, you need ( n ) such that ( 2^n = 64 ), which means ( n = 6 ).
A 4-input decoder can produce (2^n) outputs, where (n) is the number of inputs. For a 4-input decoder, (n = 4), so the number of possible outputs is (2^4 = 16). Therefore, a 4-input decoder can generate 16 distinct output lines based on the 4 input combinations.
Decoder is a circuit which have n inputs and 2^n outputs.I think you want to say encoder which have 2^n input and n output lines. So your required chip is 8(2^3)X3 encoder which does not exist.
A full adder can be implemented using a decoder by utilizing a 3-to-8 line decoder to decode the three input bits: A, B, and Carry-in (Cin). The decoder generates eight output lines corresponding to all possible combinations of the three inputs. The outputs of the decoder can then be combined with logic gates to derive the Sum and Carry-out outputs of the full adder. Specifically, the Sum output can be generated by ORing the appropriate outputs of the decoder, and the Carry-out can be derived from a combination of specific outputs as well.
It is a data selector. There are 16 digital input lines, 4-bit decoder, strobe and output pin. So you put a 4-bit binary number from 0-15 into ABCD bits and the corresponding input value is found on output at the strobe time.
In the context of digital electronics, "tb" typically refers to the timing behavior or timing diagram for a decoder, specifically a 4-to-16 line decoder. A 4-to-16 decoder takes 4 input binary signals and decodes them into one of 16 output lines, with only one output being active (logic high) at any time corresponding to the binary value of the inputs. The timing diagram would illustrate the relationship between the input signals and the active output over time, showing the propagation delay as the input changes and the output stabilizes.
Time division space switching:-suppose there are 'n' input lines and 'n' output lines connected to the bus each via switches.The switches being controlled by the decoder using the counters and control memory etc.So in the most basic form there is a counter connected to an n to 2^n decoder which controls the connection of the input and the output line to the bus.2 basic types are:input controlled time division switchingoutput controlled time division switching
The 74LS138 is a 3-to-8 line decoder that takes 3 input binary signals and activates one of eight output lines based on those inputs. It features three select inputs (A0, A1, A2) that determine which output (Y0 to Y7) will be low (active), while all other outputs remain high (inactive). The decoder also has enable inputs to control its operation; if the enables are not activated, none of the outputs will be activated. This device is commonly used in memory address decoding and data routing applications.
mohammed.eng.2005@gmail.com ---- The differences between these two circuits is subtle, as far as I can tell. A demux simply selects an output line, nothing more. It's a glorified switch. A decoder takes n inputs, and uses those inputs to determine which of the 2^n output lines is high. This is the difference, I think. A decoder is designed to simply keep one line high. A demux is designed to set one output equal to the input (whether it be high, low, or a changing signal).
the basic difference is that there is 1 input line for the demux whereas a decoder has no input lines