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If the length of a side of an equilateral triangle = 8√3, then the altitude bisects the base

forming a right angled triangle. The side measuring 8√3 is the hypotenuse, the altitude (A) is one leg and half the base length is the second leg.

By Pythagoras, (8√3)2 = (4√3)2 + A2 : A2 = (64 x 3) - (16 x 3) = 48 x 3 = 144

Therefore the altitude, A = √144 = 12

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Q: What is the length of an altitude of an equilateral triangle whose side length is 8 square root of 3?
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