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What are the factors and prime factors of 1300?
The factors of 1300 are the numbers that can be multiplied together to equal 1300. These include 1, 2, 4, 5, 10, 20, 25, 26, 50, 52, 65, 100, 130, 260, 325, and 650. The prime factors of 1300 are the prime numbers that can be multiplied together to equal 1300, which are 2, 5, and 13. Therefore, the prime factorization of 1300 is 2^2 * 5^2 * 13.
What are all the prime numbers between 1300 and 1400?
1301, 1303, 1307, 1319, 1321, 1327, 1361, 1367, 1373, 1381, 1399.
Are 145 and 1300 relatively prime?
No, they are not relatively prime.No.
What is the prime factorization of the number 1300 with exponents repeated factors appear?
22 x 52 x 13 = 1300
What is the prime factor of 1300 with exponents when repeated factors appear?
2^2 x 5^2 x 13
What is Prime factorization of 1300?
As a product of its prime factors: 2*2*5*5*13 = 1300
What is the prime factorization for the number 1300 using exponets?
The prime factorization of 1300 is 2^2 * 5^2 * 13.
What are the prime numbers from 1300-1400?
1301, 1303, 1307, 1319, 1321, 1327, 1361, 1367, 1373, 1381, and 1399
What are the factors and prime factors of 1300?
The factors of 1300 are the numbers that can be multiplied together to equal 1300. These include 1, 2, 4, 5, 10, 20, 25, 26, 50, 52, 65, 100, 130, 260, 325, and 650. The prime factors of 1300 are the prime numbers that can be multiplied together to equal 1300, which are 2, 5, and 13. Therefore, the prime factorization of 1300 is 2^2 * 5^2 * 13.
What are all the prime numbers between 1300 and 1400?
1301, 1303, 1307, 1319, 1321, 1327, 1361, 1367, 1373, 1381, 1399.
What is the 2 numbers that multiply each other to get 1300?
2600
Are 145 and 1300 relatively prime?
No, they are not relatively prime.No.
Is 1300 prime?
1300 is not a prime number. Its positive integer factors are: 1, 2, 4, 5, 10, 13, 20, 25, 26, 50, 52, 65, 100, 130, 260, 325, 650, 1300
How do you write 1300 in numeric numbers?
Exactly as it is 1300 but if you mean in Roman numerals then it is MCCC
What is the prime factorization of 1300 using exponents?
1300 = 2 * 2 * 5 * 5 * 13 = 22 * 52 * 13
What is the prime factorization of the number 1300 with exponents repeated factors appear?
22 x 52 x 13 = 1300
Who was the prime minister of Romania in 1300-1600?
In this period any Romanian principality hadn't a prime minister !
