2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293.
1300 is a composite number because it has factors other than 1 and itself. It is not a prime number.The 18 factors of 1300 are 1, 2, 4, 5, 10, 13, 20, 25, 26, 50, 52, 65, 100, 130, 260, 325, 650, and 1300.The proper factors of 1300 are 1, 2, 4, 5, 10, 13, 20, 25, 26, 50, 52, 65, 100, 130, 260, 325, and 650 or,if the definition you are using excludes 1, they are 2, 4, 5, 10, 13, 20, 25, 26, 50, 52, 65, 100, 130, 260, 325, and 650.The prime factors of 1300 are 2, 2, 5, 5, and 13. Note: There is repetition of these factors, so if the prime factors are being listed instead of the prime factorization, usually only the distinct prime factors are listed.The 3 distinct prime factors (listing each prime factor only once) of 1300 are 2, 5, and 13.The prime factorization of 1300 is 2 x 2 x 5 x 5 x 13 or, in index form (in other words, using exponents), 22 x 52 x 13.NOTE: There cannot be common factors, a greatest common factor, or a least common multiple because "common" refers to factors or multiples that two or more numbers have in common.
1301, 1303, 1307, 1319, 1321, 1327, 1361, 1367, 1373, 1381, 1399.
No, they are not relatively prime.No.
22 x 52 x 13 = 1300
To find 1300 minus 500, you can use the basic fact of subtraction that states you can break down the numbers into smaller, more manageable parts. For example, you can subtract 500 from 1300 by thinking of it as 1300 - 500 = 1300 - 400 - 100. This simplifies the calculation, allowing you to first find 1300 - 400, which equals 900, and then subtract 100 to get 800.
As a product of its prime factors: 2*2*5*5*13 = 1300
The prime factorization of 1300 is 2^2 * 5^2 * 13.
1301, 1303, 1307, 1319, 1321, 1327, 1361, 1367, 1373, 1381, and 1399
1300 is a composite number because it has factors other than 1 and itself. It is not a prime number.The 18 factors of 1300 are 1, 2, 4, 5, 10, 13, 20, 25, 26, 50, 52, 65, 100, 130, 260, 325, 650, and 1300.The proper factors of 1300 are 1, 2, 4, 5, 10, 13, 20, 25, 26, 50, 52, 65, 100, 130, 260, 325, and 650 or,if the definition you are using excludes 1, they are 2, 4, 5, 10, 13, 20, 25, 26, 50, 52, 65, 100, 130, 260, 325, and 650.The prime factors of 1300 are 2, 2, 5, 5, and 13. Note: There is repetition of these factors, so if the prime factors are being listed instead of the prime factorization, usually only the distinct prime factors are listed.The 3 distinct prime factors (listing each prime factor only once) of 1300 are 2, 5, and 13.The prime factorization of 1300 is 2 x 2 x 5 x 5 x 13 or, in index form (in other words, using exponents), 22 x 52 x 13.NOTE: There cannot be common factors, a greatest common factor, or a least common multiple because "common" refers to factors or multiples that two or more numbers have in common.
1301, 1303, 1307, 1319, 1321, 1327, 1361, 1367, 1373, 1381, 1399.
2600
No, they are not relatively prime.No.
1300 is not a prime number. Its positive integer factors are: 1, 2, 4, 5, 10, 13, 20, 25, 26, 50, 52, 65, 100, 130, 260, 325, 650, 1300
Exactly as it is 1300 but if you mean in Roman numerals then it is MCCC
1300 = 2 * 2 * 5 * 5 * 13 = 22 * 52 * 13
22 x 52 x 13 = 1300
In this period any Romanian principality hadn't a prime minister !