Algorithm to find the sum of first n natural numbers:
1. Read n.
2. Initialize N=1.
3. Initialize sum S=0.
4. Calculate S=S+N.
5. Calculate N=N+1.
6. If N>n, then goto step 7 else goto step 4.
7. Write the sum S.
8. Stop.
2520 is the smallest multiple of of first ten natural numbers.
The sum of the first 50 natural numbers is 1,251.
1 Sum of first n natural numbers = n(n+1)2[Formula.]2 Arthmetic mean of first n natural numbers = Sum of the numbers n[Formula.]3 = n(n+1)2n = n+124 So, the Arthmetic mean of first n natural numbers = n+12
1,2,3,4,5,6
It is 80*81/2 = 3240
printf ("%g\n", (n+1.0)/2);
Q.1 Write a program to print first ten odd natural numbers. Q.2 Write a program to input a number. Print their table. Q.3 Write a function to print a factorial value.
Look up Gauss' Formula if you want to know how to calculate this. If you just want the answer, it's 20100.
Here's a simple Java program that uses a for loop to generate the first 10 multiples of the first 10 natural numbers: public class Multiples { public static void main(String[] args) { for (int i = 1; i <= 10; i++) { System.out.print("Multiples of " + i + ": "); for (int j = 1; j <= 10; j++) { System.out.print(i * j + " "); } System.out.println(); } } } This program iterates through the first 10 natural numbers and prints their multiples from 1 to 10.
First you will need to have some basic programming knowledge. You can use this to help make the program that is needed.
int first= 1;
2520 is the smallest multiple of of first ten natural numbers.
The sum of the first 50 natural numbers is 1,251.
1 Sum of first n natural numbers = n(n+1)2[Formula.]2 Arthmetic mean of first n natural numbers = Sum of the numbers n[Formula.]3 = n(n+1)2n = n+124 So, the Arthmetic mean of first n natural numbers = n+12
Just write a method or function that calculates the LCM for two numbers at a time. Then calculate the LCM for the first two numbers, get the LCM of the result with the third number, etc.Just write a method or function that calculates the LCM for two numbers at a time. Then calculate the LCM for the first two numbers, get the LCM of the result with the third number, etc.Just write a method or function that calculates the LCM for two numbers at a time. Then calculate the LCM for the first two numbers, get the LCM of the result with the third number, etc.Just write a method or function that calculates the LCM for two numbers at a time. Then calculate the LCM for the first two numbers, get the LCM of the result with the third number, etc.
123456789101112131415.
The sum of the first 200 natural numbers is 20,001.