It is 80*81/2 = 3240
463
61 + 67 + 71 + 73 + 79 = 351
There are four pairs of prime integers whose sum is 80. They are: (7, 73) (13, 67) (19, 61) (37, 43)
It is: 8+16+24+32 = 80
The prime numbers between 50 and 80 are 53, 59, 61, 67, and 71. A prime number is a natural number greater than 1 that cannot be formed by multiplying two smaller natural numbers. In this range, these numbers are divisible only by 1 and themselves, making them prime.
The sum of the first sixteen numbers of pi is 80.
40 * * * * * The correct answer is 6400.
The numbers are: -10 and -8
To find the 4th number needed to achieve an average of 80, first calculate the total sum of the current 3 numbers, which is (3 \times 78 = 234). For an average of 80 with 4 numbers, the total sum must be (4 \times 80 = 320). Therefore, the 4th number can be found by subtracting the sum of the first 3 numbers from the desired total: (320 - 234 = 86). Thus, the 4th number needed is 86.
To find the fifth number, you can use the formula for finding the average of a set of numbers. The sum of the 5 numbers is 82 * 5 = 410. The sum of the 4 known numbers is 80 * 4 = 320. Therefore, the fifth number can be found by subtracting the sum of the 4 known numbers from the sum of all 5 numbers: 410 - 320 = 90. So, the fifth number is 90.
929
3240
25,20,5,30
172
463
If the question excludes the endpoint 160 then: I guess that you could reason as follows:2 + 158 = 1604 + 156 = 160...78 + 82 = 160There are 39 pairs that add up to 160 plus one 80 that is not paired.(39 * 160) + 80 = 6320If the question is meant to include the endpoint 160 ,then (40 * 160) + 80 = 6480
33 and 47