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How do you find the argument of the complex number -2-i?
arg(-2-i) = sqrt[22 + 12] = sqrt(5)
What is the answer to this -5-12i?
This is a complex number, not an algebraic expression. The letter i represents the imaginary unit (which is equal to sqrt(-1)). Graphiclly, with real numbers on a horizontal axis, and imaginary numbers on a vertical axis, this means starting at the origin, go to the left 5 units, and then go down 12 units.
How do you find the ratio of 9 to 12?
9 to 12 is the ratio. BUT, if you simplify it (divide them both by the same number which makes both of them come out to a whole number) it's 3 to 4
How do you simplify 158 over 12?
To simplify 158/12, divide 158 by 12. The answer is 13 remainder 2. 13 is a whole number. Now, pit the 2 over 12. It is 2/12, but it needs to be simplified, so divide the denominator and numerator by 2. The answer is 1/6. Put it with the 13 and the final answer is 13 1/6.
What is 12 over 21 as a simplify fraction?
4/7
Simplify the imaginary number square root of negative twelve?
-12 = 4 x 3 x -1 so sqrt = 2i root 3
Square root of -12 over 4?
sqrt(-12/4) = sqrt(-3) = +/- i*sqrt(3) where i is the imaginary sqrt of -1.
How do you simplify the square root of 12 divided by 2?
6
How do you simplify -24sqrt6 over 6sqrt12?
- 24 sqrt(6) / 6 sqrt(12) = (-24/6) sqrt(6/12) = (-4) sqrt(1/2)
How do you simplify square root of 12?
Factorise 12.Replace each pair appearing in this factorisation as by the same number outside the radical and then put everything under the radical sign. sqrt(12) = sqrt(2*2*3) = 2*sqrt(3)
What numbers added are -12 and multiply is 38?
26
What is the square root of 12 as a radical number?
sqrt(12) = sqrt(4*3) = sqrt(4)*sqrt(3) = 2*sqrt(3)
How do you solve X-3 in parentheses squared equals -12?
9
How do you simplify 12 to 16?
You can't simplify a number into a bigger number, stupid
What 2 numbers multiply to 175 but their sum is 12?
-6 +/- i*sqrt(139) where i is the imaginary square root of -1.
What is 12 root 6 minus 12 root 12?
12 sqrt(6)-12sqrt(12) = 12 [sqrt(6)-sqrt(12)] sqrt(6)=sqrt(2x3) = sqrt(2) x sqrt(3) sqrt(12)=sqrt(22x3) = sqrt(22) x sqrt(3) = 2 sqrt(3) sqrt(6) - sqrt(12) = sqrt(2) x sqrt(3) - 2 sqrt(3) = sqrt(3) [sqrt(2)-2] So 12 sqrt(6)-12sqrt(12) = 12 sqrt(3) [sqrt(2)-2]
What is 2x squared plus 24 equal zero?
so x squared + 12 = 0 so xsquared = -12 which lands you in the realm of imaginary numbers. The square root of -12 is 2i root 3 where i is the imaginary sqrt of -1.
